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marysya [2.9K]
3 years ago
12

Pls Help!! I'll MARK YOU BRAINLIEST but please explain​

Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

x<16

it's the last one

Step-by-step explanation:

Multiply both sides of the inequality by

then move the constant to the right hand side and

change it's sign and

subtract by four

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The lines shown below are parallel. If the green line has a slope of 5, what is the slope of the red line?
Ratling [72]
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What is 3/4 times 6 to the power of 3
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Consider a uniform density curve defined from x = 0 to x = 8. What percent of observations fall between 1 and 5?
allsm [11]

Answer:  0.50, which is choice b

Explanation:

The interval 1 \le x \le 5 covers 5-1 = 4 units in the horizontal direction.

This is out of 8 units that span from x = 0 to x = 8 (we could say 8-0 = 8).

So we get the final result of 4/8 = 0.50

In other words, the interval from x = 1 to x = 5 covers exactly half of the interval from x = 0 to x = 8.

7 0
3 years ago
Mancini's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is what
Anvisha [2.4K]

Question:

Mancini's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is what he found.

Type of Crust Number Sold

Thin crust          312

Thick crust          245

Stuffed crust          179

Pan style                  304

Based on this information, of the next  4500 pizzas he sells, how many should he expect to be thick crust? Round your answer to the nearest whole number. Do not round any intermediate calculations.

Answer:

1060 thick crusts

Step-by-step explanation:

Given

The above table

Required

Expected number of thick crust for the next 4500

For last week data, calculate the proportion of thick crust sold

\hat p = \frac{Thick\ crust}{Total}

\hat p = \frac{245}{312+245+179+304}

\hat p = \frac{245}{1040}

\hat p = 0.235577

For the next 4500;

n = 4500

The expected number of thick crust is (E(x)):

E(x) = \hat p * n

E(x) = 0.235577 * 4500

E(x) = 1060.0965

E(x) \approx 1060

3 0
3 years ago
On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
KIM [24]
To determine the total distance traveled by an object in constant speed, just multiply the speed by the time. So, for the car, the total distance traveled is,
                               distance by car = (20 m/s)(5s) = 100 m
For decelerating object, the distance traveled is,
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For the truck,
         distance by truck = (20 m/s)(10s) - (2m/s^2)((10s)^2)/2 = 100 m

Relatively, both have traveled the same distance. 
7 0
3 years ago
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