I believe it is C but I’m not sure
160/4=40 so each side is 40. Divide the perimeter by how many sides you have.
-4.75= z/2
Multiply both sides by 2
-4.75(2)= z/2(2)
Cross out 2 and 2, divide by 1 and becomes z
z=-9.5
Answer: z= -9.5
The answer is B. Thank you
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
