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3 years ago

Hi what is the answerr??

Mathematics

1 answer:

inna [77]3 years ago

7 0

Given:

The rule of input and output function is:

$25-g$

To find:

The answer if we put 19.

Solution:

Consider the input and output function is:

$f(g)=25-g$

Substitute $g=19$ , we get

$f(19)=25-19$

$f(19)=6$

Therefore, the required answer is 6.

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Can u please help me?!?!

ivolga24 [154]

Answer:

Step-by-step explanation: yes

8 0

2 years ago

You have a normal distribution of hours per week that music students practice. The mean of the values is 8 and the standard devi

Aleks04 [339]

Answer:

25%

Step-by-step explanation:

Since Normal Distribution is symmetrical Distribution and 5.3 and 10.7 are both 2.7 below and 2.7 above the mean respectively.

So, % of students less than 5.3 hours per week is 25%

5 0

3 years ago

A professor thinks that the students in her statistics class this term are less creative than most students at this university.

choli [55]

Answer:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

Step-by-step explanation:

$\mu=35\\n=23\\\=x=33\\s=5\\\alpha=0.1$

1. Null and alternative hypothesis

$H_{0}:\mu=35\\H_{1}:\mu$

2. Significance level

$\alpha=0.1\\1-\alpha=0.99$

Freedom degrees is given by:

$v=n-1\\v=23-1=22$

For a sgnificance level of 0,01 and 22 freedom degrees, t-student distribution value is:

$t_{0.01;23}=-2. 5083$

3. Test statistic

$t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }$

$t=\frac{33-35}{\frac{5}{\sqrt{23} } }$

$t=-1,918$

In this case, we have an one left tailed analysis, it means that null hypothesis is rejected if $t$

$-1.918>-2.5083$

Conclusion:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

3 0

3 years ago

Which of the following is the correct factored form of the given equation? 4x 2 - 11x + 6 = 0

Murljashka [212]

$4x^2-11x+6=0\\\\4x^2-8x-3x+6=0\\\\4x(x-2)-3(x-2)=0\\\\(x-2)(4x-3)=0$

3 0

3 years ago

A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o

vivado [14]

Since $\rho=\dfrac mV$ (density = mass/volume), we can get the mass/weight of the liquid by integrating the density $\rho(x,y,z)$ over the interior of the tank. This is done with the integral

$\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx$

which is more readily computed in cylindrical coordinates as

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}$

7 0

3 years ago