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3 years ago

Can some one help? anyone can earn brianlest

Mathematics

2 answers:

Katena32 [7]3 years ago

5 0

It isssssssssssssssssssssss A

alina1380 [7]3 years ago

4 0

A is the correct answer can I please get brainliest

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What is the answer (X^2)(X)(4)

enot [183]

Answer:

Simplified: 4X^3

Step-by-step explanation:

Simplify the expression.

3 0

2 years ago

The function L = 0.8T^2 models the relationship between L, the length in feet of a pendulum, and T, the period in seconds of the

Semmy [17]

The correct option is "d".
Given that L = 0.8T²
length of pendulum = 30ft

L= 0.8T²
30 = 0.8T²
T² = 30 / 0.8
T² = 37.5
T = √37.5 = 6.1 seconds
<span>So, 6.1 is the closest to the period in seconds for a pendulum that is 30 ft long.</span>

7 0

3 years ago

The length of a rectangle is 6 inches longer than it’s width what are the possible widths if the area of the rectangle is at lea

stealth61 [152]

Let the width = x

length = x + 6

(x + 6) * x = 667

Simplify

x² + 6 = 667

x² + 6 (-6) = 667 (-6)

x² = 661

√x² = √661

x = √661

x = 25.71 (rounded)

25.71 in. is your width

hope this helps

6 0

3 years ago

A rectangle is 5 times as long as it is wide. The perimeter is 50 cm. Find the dimensions of the rectangle. Round to the nearest

n200080 [17]

Answer:

Dimensions = 21 centimeters by 4.2 centimeters.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangle = 50cm

Translating the word problem into an algebraic expression, we have;

L = 5W

To find the dimensions of the rectangle;

Perimeter of rectangle = 2L + 2W

50 = 2L + 2W

50 = 2(5W) + 2W

50 = 10W + 2W

50 = 12W

W = 50/12

W = 4.2 cm.

To find the length;

L = 5W

L = 5*4.2

L = 21 cm.

8 0

3 years ago

A random sample of 100 observations from a quantitative population produced a sample mean of 22.8 and a sample standard deviatio

natima [27]

Answer:

We conclude that the population mean is 24.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 24

Sample mean, $\bar{x}$ = 22.8

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 8.3

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 24\\H_A: \mu \neq 24$

We use Two-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{22.8 - 24}{\frac{8.3}{\sqrt{100}} } = -1.44$

We calculate the p-value with the help of standard z table.

P-value = 0.1498

Since the p-value is greater than the significance level, we accept the null hypothesis. The population mean is 24.

Now, $z_{critical} \text{ at 0.05 level of significance } = \pm 1.96$

Since, the z-statistic lies in the acceptance region which is from -1.96 to +1.96, we accept the null hypothesis and conclude that the population mean is 24.

7 0

3 years ago