Answer:
-5.4c
Step-by-step explanation:
We're combining two "like" terms here.
It may make the problem easier to visualize if we write one of these terms over the other, as follows:
-2.6c
- 2.8c
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Adding, we get:
-2.6c
- 2.8c
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- 5.4c (answer)
If you would like to know which subtraction expression has the difference 1 + 4i, you can calculate this using the following steps:
a. (–2 + 6i) – (1 – 2i) = –2 + 6i – 1 + 2i = –3 + 8i
b. (–2 + 6i) – (–1 – 2i) = <span>–2 + 6i + 1 + 2i = </span>–1 + 8i
c. (3 + 5i) – (2 – i) = 3 + 5i – 2 + i = 1 + 6i
d. (3 + 5i) – (2 + i) = 3 + 5i – 2 – i = 1 + 4i
The correct result would be <span>d. (3 + 5i) – (2 + i).</span>
- cos ( 1/2 x + 1/5 π ) = 0 ( and because if cos α = 0, α= π/2 + k π, k ∈ Z )
1/2 x + π/5 = π/2 + k π, k ∈ Z
1/2 x = π/2 - π/5 + k π / * 2
x = π - 2π/5 + 2 k π
x = 3/5 π + 2 k π = 0.6 π + 2 k π
Answer:
If k = 0: x 1 = 0.6 π = 3π/5
k = 1 : x 2 = 2.6 π = 13π/5
The sum of cubes is given as:
a³ + b³ = (a + b)(a² - ab + b²)
Example for the sum of cubes:
64x³+y³ ⇒ This is the sum of cubes because each term; 64, x³, and y³ are cube numbers
By writing each term as an expression of cube numbers, we have:
(4x)³ + (y)³ ⇒ 64 is 4³
Use the factorization of the sum of cubes, we have:
(4x + y) ( (4x)²- 4xy + y²)
(4x + y) (16x² - 4xy + y²)
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The difference of cubes can be factorized as:
(x³ - y³) = (x - y)(x² + xy + y²)
Example
(125x³ - 8y³) = (5x - 2y) ((5x)² + (5x)(2y) + (2y)²)
= (5x - 2y) (25x² + 10xy + 4y²)
Answer:
the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
Step-by-step explanation:
Given the data in the question;
we know that;
the coefficient of determination is r²
while the correlation coefficient is defined as r = √(r²)
The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.
Now, given that class attendance explained 16% of the variation in grade index among the students.
so
coefficient of determination is r² = 16%
The correlation coefficient between percent of classes attended and grade index will be;
r = √(r²)
r = √( 16% )
r = √( 0.16 )
r = 0.4
Therefore, the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
