Tenth: 243.9
Hundredth: 243.88
Ten: 240
Hundred: 200
x^2 - 4
------------------------------
x + 7 | x^3 + 7x^2 - 4x - 28
x^3 + 7x^2
------------------
0 - 4x - 28
-4x - 28
-------------
0
Now we know that
x^3 + 7x^2 - 4x - 28 = (x^2 - 4)(x + 7)
x^2 - 4 can be factored since it is the difference of two squares.
x^2 - 4 = (x + 2)(x - 2)
The complete factoring is:
x^3 + 7x^2 - 4x - 28 = (x +2)(x - 2)(x + 7)
Jed's bank account balance yesterday = -$26.34
Jed's account balance now = $42.18
So Jed's balance has recovered from a negative balance to a positive balance. Now it is required to find the amount of money jed deposited to reach this state.
Let us assume that money deposited by Jed = X
Then
X -26.34 = 42.18
X = 42.18 + 26.34
= 68.52
So Jed deposited $68.52 in his account.
Answer:
![303.3 \leq \mu \leq 413.6](https://tex.z-dn.net/?f=%20303.3%20%5Cleq%20%5Cmu%20%5Cleq%20413.6)
We need to remember that the confidence interval for the true mean is given by:
![\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%5Cpm%20t_%7B%5Calpha%2F2%7D%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim
Step-by-step explanation:
We know that they use a sample size of n =20 and the confidence interval for the true mean skidding distance along a new road in a European forest is given by:
![303.3 \leq \mu \leq 413.6](https://tex.z-dn.net/?f=%20303.3%20%5Cleq%20%5Cmu%20%5Cleq%20413.6)
We need to remember that the confidence interval for the true mean is given by:
![\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%5Cpm%20t_%7B%5Calpha%2F2%7D%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
Since the upper limit for the confidence interval is lower than the value of 425 we don't have enough evidence to conclude that the the mean skidding distance is at least 425 meters at the 5% of signficance used so then the confidence interval not support the loggers claim