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2 years ago

Chemically balance the equation: Mg(HCO3)2 + HCL --> MgCl2 + CO2 + H2O

Chemistry

1 answer:

quester [9]2 years ago

8 0

Answer:

Mg(HCO3)2 + 2HCl → 2CO2 + 2H2O + MgCl2

Explanation:

Mg(HCO3)2 + 2HCl → 2CO2 + 2H2O + MgCl2

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A solution is made by dissolving 9.74 g of sodium sulfate in water to a final volume of 165 mL of solution. What is the weight/w

MatroZZZ [7]

Answer: The weight/weight % or percent by mass of the solute is 5.41 %.

Explanation:

Mass of the sodium sulfate,w = 9.74 g

Volume of the water = 165 mL

Density of the water = 1 g/mL

$Density=1 g/mL=\frac{\text{Mass of water}}{\text{Volume of water}}$

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Mass of solute + Mass of solvent =9.47 g + 165 g=174.47 g

$w/w\%=\frac{w\times 100}{W}=\frac{9.45 g\times 100}{174.47 g}=5.41 \%$

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Chemically balance the equation: Mg(HCO3)2 + HCL --> MgCl2 + CO2 + H2O​

Chemically balance the equation: Mg(HCO3)2 + HCL --> MgCl2 + CO2 + H2O