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Zinaida [17]
3 years ago
8

What is the better estimate for the height of a desk,1 meter or 1 kilometer

Mathematics
1 answer:
katovenus [111]3 years ago
5 0
Hello!

The best estimate for the height of a desk is a meter. One kilometer is equal to 1,000 metres. A desk is obviously not 1,000 metres high because, well, our roofs wouldn't be that high!
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Paula can make 14 beaded bracelets in an hour.Tina can make 13 bracelets in an hour.In one week,Paula made bracelets for 6 hours
Leno4ka [110]
Paula would be 14 times 6 or 84
Tina would be 13 times 8 or 104
So tina made more
4 0
3 years ago
How to do this please and what's the answer ​
nalin [4]
This is how you do it! Please let me know if you need help.

5 0
3 years ago
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
Given the system of equations, what is the solution? 5x - 4y = 7 x = 5 - 3/2 y
xenn [34]
The answer is A


You can solve this by equation the two equations, by substitution method or elimination. Let's choose the substitution since Equation 2 has already X isolated
-take the X in equation 2 and substitute in the first equation
So, You should have 5 (5-3/2 y) -4y =7
Get y ( I'll assume you know how to simplify and find y by yourself )
y=36/23
-Now take y and substitute it in the first equation or the second equation (it doesn't really matter)
Substituting y in Equation 2:
x=5- 3/2 (36/23)
=> x= 61/23

So answer is A where (x,y) is (61/23, 36/23)
8 0
3 years ago
Read 2 more answers
A sample of 38 students is chosen from a student body where 58% of all students own cell phones. If 24 of the students in this s
Dmitry [639]

Answer:

the sample proportion is higher

Step-by-step explanation:

What we must do is calculate the proportion of the population, we are left with the fact that out of 38 students 58% have cell phones, these are the proportion of the population, then they would be:

38 * 58% = 22.04 students

Now, the sample proportion is 24.

Therefore 22.04 < 24

Which means the sample proportion is higher

8 0
3 years ago
Read 2 more answers
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