The electric force between two charged particles can be increased by decreasing the distance between the two particles.
<h3>How to increase electric force between two charged particles.</h3>
The technique of decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. while
increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.
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<h2>The work done = - 2 x 10⁴ J</h2>
Explanation:
In the first case , the volume is kept constant and pressure varies .
In isothermal process , the work done
W₁ = V x ΔP
here V is the volume of gas and ΔP is the change in pressure
Thus W₁ = 0
Because there is no change in volume , therefore displacement is zero .
In second case pressure is constant , but volume changes
Thus W₂ = P x ΔV
here P is the pressure and ΔV is the change in volume
Therefore W₂ = 4 x 10⁵ x 5 x 10⁻² = 2 x 10⁴ J
The total work done W = - 2 x 10⁴ J
Because the work done in compression is negative .
Answer:
<h2>The coefficient of static friction will be
0.7</h2>
Explanation:
Given data
the radius of curve= 90m
speed v= 90 km/h to m/s = (90*100)/60*60= 25 m/s
we know that the expression for the centripetal force acting on the car
-------1
we also know that the expression for the frictional force between road and tire.
Ff= μmg--------2
Equating equation 1 and 2 we have
μmg= mv^2/r
μ= v^2/gr
substituting the values of speed and radius we have (assuming g= 9.81m/s^2)
μ= 25^2/9.81*90
μ= 625/882.9
μ= 0.7
Answer: A
Explanation: the principle of friction with swinging and colliding balls.
Answer:
A theory is a system of ideas intended to explain something, and a hypothesis is an educated guess.
Explanation: Hope this Helps! :)
