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alukav5142 [94]
3 years ago
5

Alguien que sepa de electromecánica porfavor

Physics
1 answer:
kkurt [141]3 years ago
8 0
LAPA HDIDOSHSUWJWVWIHDHDOSSHSVWIME
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In the early twentieth century, _______ redefined psychology as "the science of observable behavior."
Paha777 [63]

Explanation:

Answer :

A. John B. Watson

4 0
3 years ago
A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 n directed at an angle of 15° below the
Kobotan [32]

Answer:

Acceleration of the crate is 0.362 m/s^2.

Explanation:

Given:

Mass of the box, m = 40 kg

Applied force, F = 15 N

Angle at which the force is applied, (\theta) = 15°

We have to find the magnitude of the acceleration.

Let the acceleration be "a".

FBD is attached with where we can see the horizontal and vertical component of force.

⇒ F_x=Fcos(\theta)          and             ⇒ F_y=Fsin (\theta)

⇒ F_x=15cos(15)                           ⇒ F_y=15sin (15)

⇒ Applying concept of  forces.

⇒ \sum F_x=F_n_e_t =F-f

⇒ F_n_e_t =F-f

⇒ ma =F-f       <em>  ...Newtons second law Fnet = ma</em>

⇒ a =\frac{F-f}{m}              

⇒ Plugging the values.

⇒ a =\frac{15cos(15)-0}{40}     <em>...f is the friction which is zero here.</em>

⇒ a =\frac{14.48}{40}

⇒ a=0.362\ ms^-^2

Magnitude of the acceleration of the crate is 0.362 m/s^2.

4 0
3 years ago
What's the noun in "she is my favorite english teacher"
OleMash [197]

Answer:

i think it is <u>teacher</u>

Explanation:

because it is noun

7 0
3 years ago
Read 2 more answers
A mass on a string is swung in a circle of radius 0.75m at 7.0m/s.what its rate of acceleration.​
Ulleksa [173]

Explanation:

ac = v^2/r

= (7.0 m/s)^2/(0.75 m)

= 65 m/s^2

3 0
3 years ago
Please help.
cestrela7 [59]
Hello,

<span>A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and returns with a frequency of 1250 Hz. 

How fast is the vehicle going?

Doppler equation formula: </span>ƒL = ƒS(v - vL)/(v - vS)

The wave returns with a frequency of 1250 Hz, the <span>echo frequency is higher; the car must be traveling towards the police car. 

</span><span>The wave echo is coming back towards the police car at the same speed as the sound wave travels towards the moving car so t</span><span>he relative speed between the cars is half of the speed of the echo.

* </span><span>speed of sound equals about 337 m/s </span>

2v / 337 = (1250/1200) - 1 
<span>2v = 14.04 m/s </span>
<span>v = 7.02 m/s
</span>
Thus, the vehicle is going 7.02 m/s.

Faith xoxo

3 0
4 years ago
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