4y ≥ 3x + 2
Plugging in the values in the options, then the required values are when x = 6 and y = 5, then
4(5) ≥ 3(6) + 2
20 ≥ 18 + 2
20 ≥ 20
Answer:
x=3 and y=2
Step-by-step explanation:
1.) 4x+3(5x-13)=18
expand into 4x+15x-39=18
18+39= 57
15x+4x= 19x
57/19= 3 so x=3
substitute 3 into y= 5x - 13
and you get 2 so y=2
I mean I think so I’m not completely sure it’s a really hard question
Answer:
18.852:50.272
Step-by-step explanation:
Step one:
given
The radii of two right circular cylinders are in the ratio 3 : 4
r1= 3
r2= 4
Their heights are in the ratio 1 : 2
h1= 1
h2= 2
Step two:
The expression for the curve surface area is
CSA= 2πrh
CAS1= 2πr1h1
CAS1= 2*3.142*3*1
CAS1= 18.852
CAS2= 2πr2h2
CAS2= 2*3.142*4*2
CAS1= 50.272
The ratio of their curved surface areas
=18.852:50.272
