Reflecting the point (x, y) over the x-axis transforms it to the point (x, -y). Then the points (x, f(x)) on the graph of f(x) will be transformed to (x, -f(x)) when the graph is reflected over the x-axis.
The reflection of the function f(x) = |x| is -f(x) = -|x|. If we name the reflected function f(x), we have
f(x) = -|x|
In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also
increases.
- Yes, 4·y = 16·x is a direct variation
Reasons:
A direct variation is a relationship that exists between two variables. It is
also known as a direct proportion which can be expressed as; y = k·x
Where <em>k</em> is a number
The given equation is 4·y = 16·x
Dividing both sides by 4 gives;

Which gives;
y = 4·x
Comparing the above equation with the equation for a direct variation gives;
y = 4·x
y = k·x
Therefore;
k = 4
The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.
Learn more about direct variation here:
brainly.com/question/6499629
x = 10.22 in
Solution:
Width of the figure = x in
Length of the figure = (2x + 5) in
Area of the figure = 260 in²
<u>To find the value of x:</u>
<em>Area of the figure = length × width</em>
length × width = 260
(2x + 5) × x = 260

Subtract 260 from both sides of the equation.

Factor the above quadratic expression.
Quadratic equation formula:




x = 10.22, x = –12.72006
Dimension of the figure cannot be measured in negative terms.
Hence x = 10.22 in.
Answer:
5866
Step-by-step explanation:
Step-by-step explanation:
the eqn is 3x-2y+10=0
slope m=-3/-2=3/2 (m=(-xcoeff/ycoeff)
eqn is
y-y1=m(x-x1)
y+5=3/2(x-2)
2y+10=3x-6
3x-2y-16=0