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ivanzaharov [21]
3 years ago
13

Which of the nonmetals is the least reactive? a) Neb) Oc) Cld) F

Chemistry
2 answers:
Black_prince [1.1K]3 years ago
6 0
I’m sure it is d)F hope that helps :>
4vir4ik [10]3 years ago
3 0

Flourine

Explanation:

The element F has a high negative (ΔeqHө) but not so high IE1 . Therefore, it is the least reactive non-metal.

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The most common form if matter in the universe is____?
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I am almost positive that the answer is: Plasmas. Let me know if im right or not please!! :)

7 0
4 years ago
What are geometric isomers?
irina [24]
<span>C. compounds that have the same atoms arranged in the same order, but with different three-dimensional orientations.</span>
3 0
3 years ago
A sample of an unknown gas with a mass of 8.21 g has a volume of 4.8064 L when the temperature is 200oC and the pressure is 1.81
Pie

Answer:

The answer to your question is M = 36.49 g

Explanation:

Data

mass = 8.21 g

volume = 4.8064 L

Temperature = 200°C

Pressure = 1.816 atm

M = ?

Process

1.- Convert temperature to °K

°K = 273 + 200

°K = 473

2.- Calculate the number of moles

n = (PV)/RT

n = (1.816)(4.8064)/(0.082)(473)

n = 0.225

3.- Calculate the molar mass

            M --------------- 1 mol

           8.21 g ---------- 0.225 moles

M = (1 x 8.21)/0.225

M = 36.49 g

4 0
3 years ago
Consider a solution that contains 0.274 M potassium chloride and 0.155 M magnesium chloride.
solong [7]

Answer:

Concentration of chloride ions = 0.584M

Explanation:

The step by step calculations is shown as attached below.

3 0
4 years ago
Calculate the ph of the solution resulting by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh
Aliun [14]

Answer:

1.60.

Explanation:

  • The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
  • The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.

<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>

<em></em>

∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.

∵ pH = - log[H⁺]

<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>

5 0
4 years ago
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