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cricket20 [7]
3 years ago
5

How many kg of carbon dioxide are used per year to produce their arm and hammer baking soda?

Chemistry
1 answer:
cestrela7 [59]3 years ago
3 0
The complete question would be as follows:

700,000 tons of baking soda are produced per year. <span>How many kilograms of carbon dioxide are used per year to produce baking soda?

We calculate as follows:

</span><span>CO2(g) + NH3(aq) + NaCl(aq) + H2O -----> NaHCO3(s) + NH4Cl(aq)
</span>
700000 tons NaHCO3 ( 907.185 kg / 1 ton ) (<span>1 kmole NaHCO3 / 84.0 kg NaHCO3) x (1 kmole CO2 / 1 kmole NaHCO3) x (44.0 kg CO2 / 1 kmole) = 3x10^8 kg CO2

Hope this answers the question. Have a nice day.</span>
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A researcher studying the nutritional value of a new candy places a 4.90 g sample of the candy inside a bomb calorimeter and com
snow_lady [41]

Answer:

449730.879 cal/g

Explanation:

Given data:

Mass of sample = 4.9 g

Change in temperature  = 2.08 °C  (275.23 k)

Heat capacity of calorimeter = 33.50 KJ . K⁻¹

Solution:

C(candy) = Q/m

Q = C (calorimeter) × ΔT

C(candy) = C (calorimeter) × ΔT / m

C(candy) =  33.50 KJ . K⁻¹ × 275.23 K / 4.90 g

C(candy) = 9220.205 KJ / 4.90 g

C(candy) =  1881.674 KJ / g

It is known that,

1 KJ /g = 239.006 cal/g

1881.674 × 239.006 = 449730.879 cal/g

8 0
3 years ago
When NaCl dissolves in water
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The sodium ion becomes hydrated. when sodium chloride dissolves in water, the sodium and chloride ions and the polar water molecules are strongly attracted to one another by ion-dipole interactions
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3 years ago
What do I mean by Water table in Water cycle
Lina20 [59]

Answer: -

After rain fall occurs, water accumulates .

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3 years ago
The combustion of ethyne, shown below unbalance, produces heat which can be used to weld metals:
Andreyy89

Answer:

3.69 g

Explanation:

Given that:

The mass m = 325 g

The change in temperature ΔT = ( 1540 - 165)° C

= 1375 ° C

Heat capacity c_p = 0.490 J/g°C

The amount of heat required:

q = mcΔT

q =  325 × 0.490 × 1375

q = 218968.75 J

q = 218.97 kJ

The equation for the reaction is expressed as:

C_2H_{2(g)} + 5O_{2(g)} \to 2CO_{2(g)} + H_2O_{(g)}   \ \   \ \ \  \Delta H^o_{reaction} = -1544 \ kJ

Then,

1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.

Thus, for 218.97 kJ, the amount of ethyne gas required will be:

= \dfrac{26 \ g}{1544 \ kJ} \times 218.97 \ kJ

= 3.69 g

3 0
3 years ago
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Answer:

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Explanation:

8 0
3 years ago
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