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3 years ago

If the atomic radius of aluminum is 0.143 nm, calculate the volume of its unit cell in cubic meters.

1 answer:

8 0

The unit cell of Aluminum is a face-centered cubic structure. This lattice unit cell consists of 4 atoms per unit cell. The volume of the unit cell is a³ where a is the length of the side of the unit cell. In terms of radius r, volume is equal to:

V = (4r/√2)³
V = (4(0.143×10⁻⁹ m)/√2)³
V = 6.62×10⁻²⁹ m³

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4 - 1 - 3 - 2 - 6 - 5

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Answer:

Option B. 4NH3(g) + 5O2(g) —> 4NO(g) + 6H2O(g)

Explanation:

The reaction between ammonia, NH3 and oxygen, O2, will produce nitric oxide and water as shown below:

NH3(g) + O2(g) —> NO(g) + H2O(g)

Now, let us balance the equation.

This is illustrated below:

NH3(g) + O2(g) —> NO(g) + H2O(g)

There are 3 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of NH3 and 6 in front of H2O as shown below:

4NH3(g) + O2(g) —> NO(g) + 6H2O(g)

There are 4 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 4 in front of NO as shown below:

4NH3(g) + O2(g) —> 4NO(g) + 6H2O(g)

Now, the are 2 atoms of O on the left side and a total of 10 atoms on the right side. It can be balance by putting 5 in front of O2 as shown below:

4NH3(g) + 5O2(g) —> 4NO(g) + 6H2O(g)

Now, we can see that the equation is balanced.

Therefore, option B gives the balanced chemical equation for the reaction.

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