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prohojiy [21]
3 years ago
13

Pls help I will fail 10th grade

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer: A

Step-by-step explanation: Okay so there are plenty of steps to this equation but to save you time, the answer is A. If your puting

you answer into decimal form it woukd equal x= 4  x= -2.5

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Whats 2099 dived by 800
sergejj [24]

Answer:

2099/800= 2.62375

Step-by-step explanation:

5 0
3 years ago
On average, Tony the turtle completes a 15-foot course in 1 minute, and Antonio the turtle completes an 18-foot course in 1 minu
marishachu [46]

Answer:

15 feet.

Step-by-step explanation:

Tony's speed = 15 ft/min.

Antonio's = 18 feet /min.

So in 5 minutes Tony travels 5*15 = 75 feet and Antonio travels 5*18 = 90 feet.

So the answer is 90-75 = 15 feet.

8 0
4 years ago
Find the selling price $280 tax 5%
Semenov [28]

Answer:

The selling price is $294

Step-by-step explanation:

5/100 (280)

0.05 * 280 = 14

5% of 280 equals 14.

To find the selling price we have to add the tax to the price.

$14 + $280 = $294

<em>The selling price is $294</em>

6 0
3 years ago
Write in simplest radical form: √208
Arte-miy333 [17]

208:2=104\\104:2=52\\52:2=26\\26:2=13\\13:13=1\\\\208=2\cdot2\cdot2\cdot2\cdot13=2^2\cdot2^2\cdot13\\\\\sqrt{208}=\sqrt{2^2\cdot2^2\cdot13}=\sqrt{2^2}\cdot\sqrt{2^2}\cdot\sqrt{13}=2\cdot2\cdot\sqrt{13}=4\sqrt{13}\\\\Answer:\ \sqrt{208}=4\sqrt{13}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a

6 0
4 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
4 years ago
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