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Slav-nsk [51]
3 years ago
6

   add and simplify  9/16=1/2=?

Mathematics
2 answers:
dolphi86 [110]3 years ago
4 0
\frac{9}{16}+\frac{1}{2}=\frac{9}{16}+\frac{8}{16}=\frac{17}{16}=1\frac{1}{16}

I hope I helped :D
Ket [755]3 years ago
3 0
9/16+ 1/2= 9/16 + 8/16= 17/16 simplified as 1 1/16 <span />
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yarga [219]

Answer:

3.59

Step-by-step explanation:

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5 0
3 years ago
Write the reciprocal of -3/7
Alex_Xolod [135]
By flipping the fraction of -3/7, you will get the fraction of -7/3 or - 2 1/3.

Therefore, the reciprocal of -3/7 is - 2 1/3.

Hope this helps!
6 0
3 years ago
Read 2 more answers
7. While waiting for a bus, Todd decided to play with consecutive numbers (whole numbers that increase in order without skipping
kvasek [131]
A. I’m not sure what this is asking but I’d guess 8,9,10

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5 0
3 years ago
Read 2 more answers
Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
3 years ago
2-(4-6x)+8=4x-(-2x-1)+5
klasskru [66]

Answer:

-4

Step-by-step explanation:

-4 but not really sure

5 0
3 years ago
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