3 years ago

Which of the following best describes a solution?

Chemistry

2 answers:

Inga [223]3 years ago

7 0

Answer:

homogeneous mixture

mrs_skeptik [129]3 years ago

3 0

The answer would be C) Homogeneous mixture

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A solution is prepared by mixing 525 mL of ethanol with 597 mL of water. The molarity of ethanol in the resulting solution is 8.

Alenkinab [10]

Answer:

$\Delta V = 234.736\,mL$

Explanation:

The quantity of moles of ethanol in the solution is:

$n_{C_{2}H_{5}OH} = \left(\frac{597\,mL}{1000\,mL} \right)\cdot \left(8.35\,\frac{mol}{L} \right)$

$n_{C_{2}H_{5}OH} = 4.985\,mol$

The mass and volume of ethanol in the solution are, respectively:

$m_{C_{2}H_{5}OH} = (4.985\,mol)\cdot \left(46.07\,\frac{g}{mol} \right)$

$m_{C_{2}H_{5}OH} = 229.658\,g$

$V_{C_{2}H_{5}OH} = \frac{229.658\,g}{0.7893\,\frac{g}{mL} }$

$V_{C_{2}H_{5}OH} = 290.964\,mL$

The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:

$\Delta V = (525\,mL+597\,mL) - (597\,mL + 290.964\,mL)$

$\Delta V = 234.736\,mL$

8 0

3 years ago

What is the molecular description of diffusion? the transfer of energy between the moving molecules the constant, organized mole

Paul [167]

The random molecular movement from higher concentration to lower concentration

5 0

3 years ago

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A nuclear reaction in which two atomic nuclei are combined to produce a single large nucleus and energy is released by the react

Naily [24]

I believe what you are looking for is Fusion<span />

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4 years ago

What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su

anastassius [24]

Answer:

$V=27992L=28.00m^3$

Explanation:

Hello,

In this case, the combustion of methane is shown below:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

$n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4$

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

$PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3$

Best regards.

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4 years ago

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Aleks [24]

Answer should be:

Cells

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3 years ago

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