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Mumz [18]
3 years ago
10

Which of the following is not a technique that could be used to separate a mixture into its components?

Chemistry
2 answers:
IrinaVladis [17]3 years ago
7 0

Answer:

Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as evaporation, distillation, filtration and chromatography.

Explanation:

You are very much welcom

777dan777 [17]3 years ago
4 0

Answer:

stirring. because it will mixup together

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12. A heterogeneous mixture is a
TEA [102]
D. mixture in which its components retain their identity

In a heterogeneous mixture, multiple substances are mixed, but they don't chemically react and they remain chemically the same.
3 0
3 years ago
How many grams are in 0.220 mol of Ne?
yawa3891 [41]

Answer:

Mass = 4.44 g

Explanation:

Given data:

Number of moles of Ne = 0.220 mol

Mass in gram = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of Ne = 20.2 g/mol

by putting values,

0.220 mol = mass/ 20.2 g/mol

Mass = 0.220 mol × 20.2 g/mol

Mass = 4.44 g

5 0
3 years ago
Enter your answer in the box provided. How many grams of helium must be added to a balloon containing 6.24 g helium gas to doubl
Archy [21]

Answer : The mass of helium gas added must be 12.48 grams.

Explanation : Given,

Mass of helium (He) gas = 6.24 g

Molar mass of helium = 4 g/mole

First we have to calculate the moles of helium gas.

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{6.24g}{4g/mole}=1.56moles

Now we have to calculate the moles of helium gas at doubled volume.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

V\propto n

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of gas  = V

V_2 = final volume of gas = 2V

n_1 = initial moles of gas  = 1.56 mole

n_2 = final moles of gas  = ?

Now we put all the given values in this formula, we get

\frac{V}{2V}=\frac{1.56mole}{n_2}

n_2=3.12mole

Now we have to calculate the mass of helium gas at doubled volume.

\text{Mass of }He=\text{Moles of }He\times \text{Molar mass of }He

\text{Mass of }He=3.12mole\times 4g/mole=12.48g

Therefore, the mass of helium gas added must be 12.48 grams.

4 0
3 years ago
What percentage of the atmosphere is carbon dioxide?.
stellarik [79]

Answer:

4%

Explanation:

the answer is 4% , hope this help

5 0
2 years ago
Determine the volume of fluid in the graduated cylinder shown.
Helen [10]

Answer:

B. 12.8 mL

Explanation:

B is the right answer because the volume of the fluid is <em>12.8</em><em> </em><em>mL</em>

5 0
3 years ago
Read 2 more answers
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