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In-s [12.5K]
3 years ago
7

How does a sample of water at 38 °C compare to a sample of water at 295 K? The water at 38 °C has a lower average kinetic energy

than the sample at 295 K. The water at 38 °C has faster-moving molecules than the sample at 295 K. The water at 38 °C has greater nuclear energy than the sample at 295 K. The water at 38 °C has larger molecules than the sample at 295 K.
Chemistry
1 answer:
Drupady [299]3 years ago
3 0

Answer:

The water at 38 °C has faster-moving molecules than the sample at 295 K.

Explanation:

Converting the temperature, 295 K from Kelvin to Celsius:

295 - 273 = 22°C

⇒The boiling point of water is 100°C  and its melting point 0°C

⇒When we compare water at those 2 different temperatures ( 22°C and 38°C) we can say that water is in liquid form at both these temperatures as both of them are quite below the boiling temperature and above the melting temperature.

⇒The difference in temperature between water at the 2 given  temperatures = 38°C - 22°C = 16°C

Water at 38°C is at a higher temperature and so is warmer than water at a lower temperature of 22°C.

At the atomic scale, the kinetic energy of atoms and molecules is sometimes referred to as heat energy. Kinetic energy is also related to the concept of temperature. Temperature is defined as the measure of the average speed of atoms and molecules. The higher the temperature, the faster these particles of matter move.

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Cuales son los numeros cuanticos con ejemplo
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Puede tomar los valores enteros positivos: n= 1, 2, 3, 4, 5, 6, 7. Por ejemplo si tengo un elemento químico que su último nivel es el 3s, su número cuántico principal sería el 3. Si tengo un elemento químico en que su último nivel es el 1s, entonces su número cuántico principal sería 1.
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3 years ago
What are two problems with building a refracting telescope with a 10-meter diameter lens?
Lena [83]

Answer:

1. Weight.

2. Large lens will tend to deflect under its own weight

Explanation:

Hello,

Weight is a big part of it. There’s a reason the largest working refractor on Earth (the Clark refractor at Yerkes Observatory in Wisconsin) has a 102-cm objective; a 125-cm lens was created for the Paris Exposition of 1900, but the accompanying telescope was a pain to use (very hard to aim) and was scrapped when no one wanted to buy it.

Lens can only be supported at its edges unlike mirrors, and a large lens will tend to deflect under its own weight unless it’s so thick that it won’t transmit much light. It is also extremely difficult to cast and polish a glass blank of such huge size, which is why (see List of largest optical refracting telescopes - Wikipedia) almost no one has tried building one in over a century.

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3 0
4 years ago
The balanced combustion reaction for C 6 H 6 C6H6 is 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ 12 CO 2 ( g ) + 6 H 2 O ( l ) + 6542 kJ 2C
Lana71 [14]

Explanation:

First, we will calculate the molar mass of C_{6}H_{6} as follows.

Molar mass of C_{6}H_{6} = 6 \times 12 + 6 \times 1

                                   = 78 g/mol

So, when 2 mol of C_{2}H{6} burns, then heat produced = 6542 KJ

Hence, this means that 2 molecules of C_{6}H{6} are equal to 78 \times 2 = 156 g of C_{6}H_{6} burns, heat produced = 6542 KJ

Therefore, heat produced by burning 5.5 g of C_{6}H{6} =                  

       6542 kJ \times \frac{5.5 g}{156 g}

            = 228.97 kJ

            = 228970 J           (as 1 kJ = 1000 J)

It if given that for water, m = 5691 g

And, we know that specific heat capacity of water is 4.186 J/g^{o}C .

As,             Q = m \times C \times (T_{f} - T_{i})

          228970 J = 5691 g \times 4.184 J/g^{o}C \times (T_{f} - 21)
^{o}C

                T_{f} - 21^{o}C = 9.616^{o}C

                T_{f} = 30.6^{o}C

Thus, we can conclude that the final temperature of the water is 30.6^{o}C.

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3 years ago
The following questions refer to the graph below, where sulfur trioxide is put into a sealed bottle and allowed to stand over ti
OleMash [197]

The concentration of the sulfur trioxide decreases with time due to its decomposition into sulfur dioxide and oxygen.

<h3>What is the balanced equation for the decomposition of sulfur trioxide into sulfur dioxide and oxygen?</h3>

The balanced equation for the decomposition of sulfur trioxide into sulfur dioxide and oxygen is given below as:

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The addition of more sulfur trioxide to the bottle will result in increase in the volume of oxygen present as equilibrium will shift towards formation of products.

The addition of more sulfur dioxide to the bottle will result in decrease in the volume of oxygen present as equilibrium will shift towards formation of sulfur trioxide due to increase in product concentration.

Based on the graph, if the bottle is sealed, the concentration of sulfur trioxide will remain in dynamic equilibrium with the concentration of the products after the second day.

Based on the above information and reaction, the best way to reduce the amount of SO3 in the atmosphere, and thus reduce the amount of acid rain is to allow it to decompose before emission into the atmosphere,

Therefore, the concentration of the sulfur trioxide decreases with time due to its decomposition into sulfur dioxide and oxygen.

Learn more about sulfur trioxide decomposition at: brainly.com/question/10982712

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user100 [1]
     The chemical symbol for sodium is Na. Hope this helped!
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