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tiny-mole [99]
3 years ago
5

What is the molecular description of diffusion? the transfer of energy between the moving molecules the constant, organized mole

cular movement from lower concentration to higher concentration the random molecular movement from higher concentration to lower concentration the concentration of heavier molecules on one side and lighter molecules on the other NextReset
Chemistry
2 answers:
otez555 [7]3 years ago
8 0

The correct answer is

The random molecular movement from higher concentration to lower concentration

:)

Paul [167]3 years ago
5 0
The random molecular movement from higher concentration to lower concentration
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What happens when Potassium Hydroxide reacts with Sulphuric Acid?​
Ede4ka [16]

As we know that neutralization reaction is a reaction in which base react with acid to form salt and water.

When Potassium Hydroxide reacts with Sulphuric Acid, it forms Potassium Sulphate and Water.

As a result of neutralization reaction, Potassium Sulphate and Water is formed.

2KOH + H2SO4 ----> K2SO4 + 2H2O

Here, K2SO4 is found in aqueous medium in neutralization reaction. It is a neutral salt.

5 0
4 years ago
Read 2 more answers
Easy Chem, Will Give brainliest
Crazy boy [7]

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

5 0
3 years ago
How many valence electrons does a fluorine atom contain?<br> a. 2<br> b. 5<br> c. 7<br> d. 9
juin [17]

F---atomic number 9---1s2 2s2 2p5 -----7 electrons

6 0
3 years ago
Gastric juice (pH 1.5) is produced by pumping HCl from blood plasma (pH 7.4) into the stomach. Calculate the amount of free ener
Annette [7]

Given question is incomplete. The complete question is as follows.

Gastric juice (pH 1.5) is produced by pumping HCl from blood plasma (pH 7.4) into the stomach. Calculate the amount of free energy required to concentrate the H in 1 liter of gastric juice at 37 degree of centigrade. Under cellular conditions, how many moles of ATP must be hydrolyzed to provide this amount of free energy? the free energy change for ATP hydrolysis under cellular conditions is about -58 kJ/mol. Ignore the effects of the transmembrane electrical potential.

Explanation:

The given data is as follows.

       Gastric juice pH = 1.5,        blood plasma pH = 7.4

    Temperature = 37^{o}C = (37 + 273) K

                           = 310 K

Now, relation between pH and concentration of hydrogen ions is as follows.

           pH = -log [H^{+}]

At pH = 1.5, we will calculate the [H^{+}] as follows.

            [H^{+}] = 10^{-pH}

                        = 10^{-1.5}

                        = 3.16 \times 10^{-2} M  (C_{2})

At pH = 7.4, we will calculate the [H^{+}] as follows.

            [H^{+}] = 10^{-pH}

                        = 10^{-7.4}

                        = 3.98 \times 10^{-8} M   (C_{1})

Also,

        \Delta G_{f} = RT ln (\frac{C_{2}}{C_{1}})

                      = 8.314 \times 310 \times ln (\frac{3.16 \times 10^{-2}}{3.98 \times 10^{-8}})

                      = 35 kJ/mol

So, the amount of ATP necessary to provide 35 kJ is as follows.

           \frac{35 kJ}{58 kJ/mol}

             = 0.6 mol

Therefore, we can conclude that 0.6 moles of ATP must be hydrolyzed to provide this amount of free energy.

7 0
3 years ago
the melting point of trimethylamine is -11.7.2, while the melting point of propylamine is -83.0 Considering that both these mlec
Simora [160]

Answer:

Due to hydrogen bond in propylamine.

Explanation:

The boiling point or melting point are property of

a) size

b) the intermolecular force of interactions.

As we know that primary and secondary amines form intermoleclar hydrogen bonds, which increases the force of attractions between molecules increasing the boiling point of amines.

However in case of tertiary amines there is no hydrogen directly attached to electronegative nitrogen atoms, thus no possibility of formation of hydrogen bond hence low boiling points.

The structures are shown in the figure.

3 0
3 years ago
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