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tiny-mole [99]
3 years ago
5

What is the molecular description of diffusion? the transfer of energy between the moving molecules the constant, organized mole

cular movement from lower concentration to higher concentration the random molecular movement from higher concentration to lower concentration the concentration of heavier molecules on one side and lighter molecules on the other NextReset
Chemistry
2 answers:
otez555 [7]3 years ago
8 0

The correct answer is

The random molecular movement from higher concentration to lower concentration

:)

Paul [167]3 years ago
5 0
The random molecular movement from higher concentration to lower concentration
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How many grams are in 4 moles of aluminum phosphate
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What temperature would 3.54 moles of xenon gas need to reach to exert a pressure of 1.57 atm at a volume of 34.6 l
ira [324]

Answer:

186.9Kelvin

Explanation:

The ideal gas law equation is PV = n R T

where

P   is the pressure of the gas

V   is the volume it occupies

n  is the number of moles of gas present in the sample

R  is the universal gas constant, equal to  0.0821 atm L /mol K

T  is the absolute temperature of the gas

Ensure units of the volume, pressure, and temperature of the gas correspond to R ( the universal gas constant, equal to  0.0821 atm L /mol K )

n = 3.54moles

P= 1.57

V= 34.6

T=?

PV = n R T

PV/nR = T

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54.322/0.290634= 186.908620464= T

186.9Kelvin ( approximately to 1 decimal place)

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3 years ago
A 25 gram(m) metal ball is heated to 200C(delta T) with 2330 Joules(q) of energy. What is the specific heat of the metal?
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Answer:

The specific heat of the metal is 0.466 \frac{J}{g*C}

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

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Replacing:

2330 J= c*25 g* 200 °C

Solving:

c=\frac{2330 J}{25 g* 200 C}

c=0.466 \frac{J}{g*C}

<u><em>The specific heat of the metal is 0.466 </em></u>\frac{J}{g*C}<u><em></em></u>

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