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professor190 [17]
3 years ago
9

A county park charges a $175 fee to rent a pavilion plus $20 per guest.

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:

y=$20x+$175

Step-by-step explanation:

$20x is the slope

$175 is the y-intercept

$20 is the slope because it is asking per person and x is how many people you have for guests. $175 is the y-intercept because you only pay it once.

Hope this helps, if not sorry.

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The cube root of 8 =2

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You buy shrimp at the market. The shrimp cost $34.99 for two 2.5-pound bags. What is the unit rate of the shrimp in dollars per
schepotkina [342]
$34.99 ... 2.5-pound bags
$x = ? ... 1 pound

If you would like to know what is the unit rate of the shrimp in dollars per pound, you can calculate this using the following steps:

34.99 * 1 = x * 2.5
34.99 = x * 2.5      /2.5
x = 34.99 / 2.5
x = $13.996 = $14

The correct result would be $14.
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Choose the function that the graph represents
gayaneshka [121]

Answer:

Where are the functions and the graph?

Step-by-step explanation:


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4 years ago
A construction company transported 8 stones that weighed a total of 70.22 kilograms. How much did each stone weigh?
pishuonlain [190]

Answer:

8.7kilos

Step-by-step explanation:

70.22 divided by 8

hope this helps!

5 0
2 years ago
Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of
Shalnov [3]

Answer:

Owl= 67.14ft

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}

22^{\circ} 8'6'' = 22.135^{\circ}

30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}

30^{\circ} 40'30'' = 30.675^{\circ}

Considering Jason's position:

tan(22.135^{\circ}) = \frac{H}{x + 48}

Where x = distance between the tree and Alison

Make H the subject

H = (x + 48)tan(22.135^{\circ})

Considering Alison's position

tan(30.675^{\circ}) = \frac{H}{x}

Make H the subject

H = xtan(30.675^{\circ})

H = H

(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})

(x + 48) *0.4068 = x* 0.5932

Open bracket

x *0.4068 + 48 *0.4068 = 0.5932x

0.4068x + 19.5264 = 0.5932x

Collect Like Terms

-0.5932x+0.4068x = -19.5264

-0.1864x = -19.5264

0.1864x = 19.5264

Make x the subject

x = \frac{19.5264}{0.1864}

x = 104.76

Substitute 104.76 for x in H = xtan(30.675^{\circ})

H = 104.76 * tan(30.675^{\circ})

H = 104.76 * 0.5932

H = 62.14

The above represents the height of the tree.

The height of the owl is:

Owl= H + 5

Owl= 62.14 + 5

Owl= 67.14ft

7 0
3 years ago
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