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3 years ago

Need help with this please

Mathematics

1 answer:

Katarina [22]3 years ago

3 0

For the first one, since she earns $17 per hour, & she tutored for 12 hrs this month, all you have to do is multiply the amount she makes per hour by the hours she’s tutored for. so 12x17=$204 so she made $204 this month. For the second one, it’d be the same thing, just multiply 19.5 by 17, which would give you 331.5.

& For the second question, all you have to do is plug in the numbers to the equation above. so it’d be 540 gallons / 1 minute multiplied by 42 since that is the time the pool needs to be filled by. So, if you do that, you will get 22,680, so the answer will be : yes it will fill up on time.

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Is a voluntary response sample (sometimes, always, or never) valid?

Katen [24]

A voluntary response sample is always valid.

5 0

4 years ago

Help me please ASAP

Mashutka [201]

Answer: $\frac{5}{35}$

Step-by-step explanation:

Since, the total number of contestant = 7,

Thus, the probability that out of 3 contestant, me and my friend is chosen

= $\frac{2_C_2\times 5_C_1}{7_C_3}$

= $\frac{\frac{2!}{2!0!}\times \frac{5!}{1!\times 4!}}{\frac{7!}{4!\times 3!}}$

= $\frac{1\times 5}{\frac{7\times 6\times 5\times 4!}{4!\times 6}}$

= $\frac{5}{35}$

⇒ Third Option is correct.

4 0

3 years ago

Calculator

Ludmilka [50]

Answer:

Step-by-step explanation:

42/21 = x/17

solve to get the answer

2 = x/17

2*17 = x/17 * 17

34 = x

5 0

3 years ago

Is d = 8 a solution to the inequality below?<br><br> 49<img src="https://tex.z-dn.net/?f=%5Cgeq" id="TexFormula1" title="\geq" a

seraphim [82]

Answer:

No

Step-by-step explanation:

49 ≥ 10d

49 ≥ 10(8)

49 ≥ 80

49 has to be greater than or equal to 80

d = 8 isn’t a solution

8 0

3 years ago

A random sample of 4000 college students yielded 2250 who are in favor of banning Hawaiian shirts. Estimate the true proportion

Andreas93 [3]

Answer: (0.5496, 0.5754)

Step-by-step explanation:

The confidence interval for population proportion (p) is given by :-

$\hat{p}\pm z*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$ , where $\hat{p}$ = Sample proportion , n= sample size , z*= Critical z-value.

Let p be the proportion of all college students who are in favor of banning Hawaiian shirt.

Given, A random sample of 4000 college students yielded 2250 who are in favor of banning Hawaiian shirts.

i.e. n=4000

$\hat{p}=\dfrac{2250}{4000}=0.5625$

z-value for 90% confidence level is 1.645

Now , 90% confidence interval for p would be :

$0.5625\pm (1.645)(\sqrt{\dfrac{0.5625(1-0.5625)}{4000}})$

$=0.5625\pm (1.645)(\sqrt{0.0000615234375})\\\\=0.5625\pm (1.645)(0.00784368774876)\\\\\approx0.5625\pm0.0129\\\\=(0.5625-0.0129, \ 0.5625+0.0129)\\\\=(0.5496,\ 0.5754)$

Hence, the required 90% interval = (0.5496, 0.5754)

6 0

4 years ago