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Annette [7]
3 years ago
15

Charles is making pumpkin lattes. His recipe calls for 2/3 cup of milk for every eighth cup of pumpkin purée. If Charles is maki

ng five pumpkin lattes, how much more milk will he use than purée?
Mathematics
1 answer:
Molodets [167]3 years ago
7 0
Are we assuming that we are using an eight of a cup of pumpkin puree per latte?
If we are then the answer would be 1.042 cups of milk more than puree.

First we have to find out how much puree we are using.
That would be ( 1/8 ) × 5 = 0.125 × 5 = 0.625 cups of puree.
Then we would find how much milk we are using.
That would be ( 2/3 ) × 5 = 0.666666 ( a lot of sixes ) × 5 = 1.666666 ( a lot of sixes ).
To find the difference, you would then have to subtract the amount of puree from the amount of milk.
You would get 1.666666 − 0.625 = 1.0416666 ( also a lot of sixes ). If you are doing this with your own calculator you should get approximately the same number.
Since the number isn't exact you can round up all the sixes to the nearest thousandth. You should get approximately 1.042 cups.
I hope this helped.
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3 years ago
Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?
aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

 two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

  consecutive terms is d, then

  U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

 the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

4 0
3 years ago
How many tens in five hundred million
Vilka [71]
Divide 5 million by ten to get five hundred thousand. Five hundred thousand is the answer
Hope this helps!
4 0
3 years ago
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ivanzaharov [21]

Answer:

ANSWER: Yes. They have enough to pay their bill: 21 dollars times 1.06 = 22 dollars and 26 cents and 22 dollars and 26 cents times 1.15 = 25 dollars and 60 cents.

Step-by-step explanation:

convert all % to decimals

0.06 x 21 = $1.26 tax

0.15 x 21 = $3.15 tip

1.26 + 3.15 = $4.41 added payment

4.41 + 21 = = $25.41 total bill

(yes i am aware i did the method differently since i learned it another way but the answer should till be correct.)

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3 years ago
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Answer:

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Step-by-step explanation:

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