angles EFH and GFH are congruents
for the second equivalence criterion two triangles are equivalents if they have respectively 2 angles and 1 side congruents
the two triangles have congruents the angle right angle (HGF and HEF) and the 55 degrees angles (EFH and GFH); then they have in common the HF side.
so the triangles are congruent and so all the sides are respectively congruent,for example EH with HG:
EH=HG
s+36=7s
s+36-7s=0
s-7s=-36
-6s=-36
6s=36
s=6
<em>sorry for my english</em>
5(x − 4)^2
5(x - 4)(x - 4)
5(x^2 - 8x + 16)
5x^2 - 40x + 80
Did you follow?
I believe the given limit is
![\displaystyle \lim_{x\to\infty} \bigg(\sqrt[3]{3x^3+3x^2+x-1} - \sqrt[3]{3x^3-x^2+1}\bigg)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bx%5Cto%5Cinfty%7D%20%5Cbigg%28%5Csqrt%5B3%5D%7B3x%5E3%2B3x%5E2%2Bx-1%7D%20-%20%5Csqrt%5B3%5D%7B3x%5E3-x%5E2%2B1%7D%5Cbigg%29)
Let

Now rewrite the expression as a difference of cubes:

Then

The limit is then equivalent to

From each remaining cube root expression, remove the cubic terms:



Now that we see each term in the denominator has a factor of <em>x</em> ², we can eliminate it :


As <em>x</em> goes to infinity, each of the 1/<em>x</em> ⁿ terms converge to 0, leaving us with the overall limit,

All four sides of a square are equal.
So if BC is 10, then AC is also 10.