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3 years ago

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The mass of the Eiffel Tower is about 9.16 ⋅ 106 kilograms. The mass of the Golden Gate Bridge is 8.05 ⋅ 108 kilograms. Approxim

ately how many more kilograms is the mass of the Golden Gate Bridge than the mass of the Eiffel Tower? Show your work and write your answer in scientific notation.
Please help or im going to faill

1 answer:

olga55 [171]3 years ago

7 0

Answer:

$7.96 *10^8kg$

Step-by-step explanation:

Given

$Eiffel = 9.16 * 10^6\ kg$

$Golden\ Gate =8.05 * 10^8kg$

Required

Determine the difference in mass

This is calculated by subtracting the mass of Eiffel tower from the mass of Golden gate bridge

$Difference = Golden\ Gate - Eiffel$

$Difference = 8.05 * 10^8 - 9.16 * 10^6$

Express $10^8$ as $10^6 * 10^2$

$Difference = 8.05 * 10^2*10^6 - 9.16 * 10^6$

Express $10^2$ as $100$

$Difference = 8.05 * 100*10^6 - 9.16 * 10^6$

$Difference = 805 *10^6 - 9.16 * 10^6$

Factorize:

$Difference = (805- 9.16) * 10^6$

$Difference = 795.84 * 10^6$

Factorize the decimal number

$Difference = 7.9584 *10^2 * 10^6$

$Difference = 7.9584 *10^8$

Approximate:

$Difference = 7.96 *10^8$

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Mrrafil [7]

Answer:

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 120 or not, the system of hypothesis would be:

Null hypothesis: $\mu = 120$

Alternative hypothesis: $\mu \neq 120$

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(z$

Step-by-step explanation:

Data given and notation

$\bar X=114$ represent the sample mean

$\sigma=22$ represent the population standard deviation

$n=36$ sample size

$\mu_o =120$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part 1

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 120 or not, the system of hypothesis would be:

Null hypothesis: $\mu = 120$

Alternative hypothesis: $\mu \neq 120$

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(z$

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The used car is priced at $2,695.

If you borrow the money for the car, your payments will be $122 a month for 30 months. This means that the total amount of money that you would have paid at the end of 30 months at a rate of $122 per month is the amount paid per month multiplied by the total number of months. It becomes

Total payment = 122×30 = $3660

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1 step:

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