Ask question

Ask question

All categories

2 years ago

10

HELPPP ASAP!!! Fernando, sixty-six, developed tremors a few years ago. Now he is becoming unsteady on his feet. Which of

2 answers:

svetlana [45]2 years ago

8 0

Parkinson’s disease.

My name is Ann [436]2 years ago

4 0

Answer:

The answer is Parkinson's Disease

Step-by-step explanation:

It is correct on Odyssey Ware

You might be interested in

Awsner this with step by step (can use calculator)

ss7ja [257]

Answer:

$x = 9.2$

$x =22.0$

$x = 8.7$

Step-by-step explanation:

Required

Find x

(a)

x is calculated using tangent formula

$\tan(57) = \frac{x}{6}$

Make x the subject

$x = 6 * \tan(57)$

$x = 6 * 1.5399$

$x = 9.2394$

$x = 9.2$ --- approximated

(b):

x is calculated using cosine formula

$\cos(60) = \frac{11}{x}$

Make x the subject

$x = \frac{11}{\cos(60)}$

$x = \frac{11}{0.5}$

$x =22.0$

(c):

x is calculated using sine formula

$\sin(60) = \frac{x}{10}$

Make x the subject

$x = 10 * \sin(60)$

$x = 10 * 0.8660$

$x = 8.660$

$x = 8.7$ --- approximated

3 0

3 years ago

An acid is prepared by mixing 400 mL of water and 100 mL of pure sulfuric acid. What is the

Natasha2012 [34]

C. 25
——-
Divide 400/100=4
——-
Than divide 4/100
—-

8 0

3 years ago

What is a equivalent ratio to 8:9

LenKa [72]

Answer:16:18

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need the inequality answer.florence wants to buy onions and doesn't want to spend no more than $3. Can she buy 2.5 pounds ? Th

Lapatulllka [165]

No because if you divide 1.25 by two to find out what the half is in 2.5, it would be .62… and since she wants to buy 2.5 pounds, you've already figured out the .5, so 1.25x2 + .62, it would be 3.12.
Illusion103

3 0

3 years ago

Read 2 more answers

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0

3 years ago