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Lunna [17]
3 years ago
12

I need help with this quesiton

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

3

Step-by-step explanation:

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I’m so confused on what numbers l should put into the boxes
Serggg [28]

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The lines for the given statements can be plotted as shown below.

<h3>What is the equation of a line?</h3>

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is y-intercept.

The lines for the given statements can be plotted as shown below.

The coordinate grid can be filled as,

1)

x        0         3         1

y        3         0         2

2.)

x        0         1         -1

y         1         0          2

3.)

x         0         4         -1

y         -2         0          2

4.)

x         0         1           1

y         -2         0         -2

Learn more about Equation of Line:

brainly.com/question/21511618

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3 0
2 years ago
What measurement do you need to know to find the volume of a cylinder?
mel-nik [20]
You do the radius times Height

7 0
3 years ago
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Someone help plss show work​
Mazyrski [523]

Answer:

Slope: \frac{3}{5}

Y-Intercept: (0,-5)

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is y=mx+b. In this case, our equation is already in this form. m is what your slope is. In this case, our

2. To find the y-intercept we look at value b that is in y=mx+b. In this case, b is -5. So, our ordered pair is (0,-5).

4 0
3 years ago
Read 2 more answers
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


3 0
4 years ago
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wright down in terms of n, an expression for the nth term of the following sequences: a) 12,10,8,6,4 b) 25,20,15,10,5
Arturiano [62]

Answer:

a)a_{n} =−2n+14

b)a_{n}  = − 5 n + 30

3 0
3 years ago
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