Answer:
![x^{2} -3x-28](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-3x-28)
Step-by-step explanation:
To find this equation in standard form, first, write it in factored form. This looks like
. Then, multiply the polynomials using the FOIL (First, Outside, Inside, Last) method.
- Following the FOIL method, you should multiply the first terms in each binomial,
, which equals
. - Then, the outside terms,
. This equals
. - Next, the inside terms,
![4*x](https://tex.z-dn.net/?f=4%2Ax)
. - Finally, the last terms,
, this equals
.
Then, add all of the terms together
. To get the standard form, combine like terms, this comes out to
.
It's not true unless my math is wrong
Answer:
5 , 10 / 2
Step-by-step explanation:
20 / 4 = 5
20 / 4 = 20/2 / 4/2 = 10 / 2 = 5
Answer:
The value of the given equation is ![\frac{1}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12%7D)
Step-by-step explanation:
Given:
![\frac{1}{2}-(\frac{2}{3} -\frac{1}{4})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D-%28%5Cfrac%7B2%7D%7B3%7D%20%20-%5Cfrac%7B1%7D%7B4%7D%29)
Solving the bracket by taking the L.C.M .
![=\frac{1}{2} -(\frac{(2)(4)-(1)(3)}{12}) \\\\=\frac{1}{2} -(\frac{8-3}{12} )\\\\=\frac{1}{2}-(\frac{5}{12} ) \\](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%20-%28%5Cfrac%7B%282%29%284%29-%281%29%283%29%7D%7B12%7D%29%20%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20-%28%5Cfrac%7B8-3%7D%7B12%7D%20%29%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D-%28%5Cfrac%7B5%7D%7B12%7D%20%29%20%5C%5C)
Now, again subtracting the terms by L.C.M
![=\frac{(1)(6)-(5)(1)}{12} \\\\=\frac{6-5}{12}\\\\=\frac{1}{12}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%281%29%286%29-%285%29%281%29%7D%7B12%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B6-5%7D%7B12%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B12%7D)
The value of the given equation is ![\frac{1}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12%7D)