If you look at the shape you see it has four triangles just find the area of them then add them together.
answer 11.6 repeating or 11 and 2/3
since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
Answer:
Width: 12 ft
Maximum area: 144 ft²
Step-by-step explanation:
A = 24x – x²
A = –x² + 24x
A = –(x² – 24x)
A = –(x² – 24x + 144) + 144
A = –(x – 12)² + 144
Therefore, the maximum area of 144 ft² occurs at x = 12 ft.
Answer:
Step-by-step explanation:
What is the slope please