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lorasvet [3.4K]
3 years ago
10

a recipe requires 1/2 cup of flour for every batch of cookies how many full batches of cookies can be made with 5 1/2 cups of fl

our
Mathematics
2 answers:
Allushta [10]3 years ago
5 0
You're answer would be 11 batches :)
Fantom [35]3 years ago
4 0
Hello There!

You want to know how many cookies can be made using 5 1/2 cups of flour.

                                             
                                                            Solving
 
                                                      1 x 2                2
                                                  --------------  =     ----- 
                                                      2 x 11             22

                                             2/22 simplified is 1/11

                         
              So, You can make 11 cookies with 5 1/2 cups of flour.

Hope this helped!
                                                 
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I think it's option c. 
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3 years ago
Which of the following shows that EFGH is a parallelogram for y=7 and z=9?
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Option B: m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Explanation:

Option A: m \angle E=m \angle F=60^{\circ} and m \angle G=120^{\circ} so \angle G is supplementary to both \angle E and \angle F, so EFGH is a parallelogram

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we get, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Thus, m \angle E\neq m \angle F because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B:  m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Hence, Option B is the correct answer.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

To determine the angles, let us substitute z=9 in  m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ}

Thus, m \angle F=m \angle G=120^{\circ}

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Adding the angles E and G, we have,

m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

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