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mash [69]
3 years ago
11

Which value is in the domain of f(x)? PLS help :)

Mathematics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

(c) 4

Step-by-step explanation:

Given

The piecewise function

Required

The value in f(x) domain

The domain of f(x) is:

-6 < x \le 0 and 0 < x \le 4

Combine both inequalities:

-6 < x \le 4

List the values of the inequality

-6 < x \le 4 = \{-5,-4,-3,-2,-1,0,1,2,3,4\}

From the list of given options

Only 4 is among the domain

Others are not

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Answer:

25%

Step-by-step explanation:

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Researchers are interested if a school breakfast program leads to taller children. Assume that the population of all 5 year-old
DedPeter [7]

Answer:

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=39 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

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3 years ago
The first thing you should do in solving a word problem is estimate what you think the answer would be.
Lelu [443]

Answer:

The answer is True.

Step-by-step explanation:

  • <u>Estimate the Answer Before Solving Having a general idea of a ballpark answer .</u>
  • <u>Or the problem lets students know if their actual answer is reasonable or not.</u>
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what is the absolute value of -8? Use the number line to help anwser the question HELP MEEEE A: -16. B= -8 C= 8 D= 16
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Answer:

Step-by-step explanation:

It wo be B= -8

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