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babymother [125]
3 years ago
9

Ooh, ooh

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Answer:

I love this songgg...

Andre45 [30]3 years ago
3 0

Answer:

that is so sweet i wish i could show my bf that but sadly  we split a few day ago and just reading that made me cry

Step-by-step explanation:

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In the diagram below, is circumscribed about quadrilateral ABCD . What is the value of ?
Olin [163]

Answer:

C

Step-by-step explanation:

There's a property of cyclis quadrilaterals that say that opposite sides will add up to 180

so we have

5x+75=180\\\\5x=180-75\\\\5x=105\\\\x=21

which is option c

5 0
3 years ago
cam hits the bullseye in 8 darts out of 15 throws. what is the experimental probability that came next throws will hit the bulls
Zigmanuir [339]

Answer:

A darts player practices throwing a dart at the bull’s eye on a dart board. Her probability of hitting the bull’s eye for each throw is 0.2.

(a) Find the probability that she is successful for the first time on the third throw:

The number F of unsuccessful throws till the first bull’s eye follows a geometric

distribution with probability of success q = 0.2 and probability of failure p = 0.8.

If the first bull’s eye is on the third throw, there must be two failures:

P(F = 2) = p

2

q = (0.8)2

(0.2) = 0.128.

(b) Find the probability that she will have at least three failures before her first

success.

We want the probability of F ≥ 3. This can be found in two ways:

P(F ≥ 3) = P(F = 3) + P(F = 4) + P(F = 5) + P(F = 6) + . . .

= p

3

q + p

4

q + p

5

q + p

6

q + . . . (geometric series with ratio p)

=

p

3

q

1 − p

=

(0.8)3

(0.2)

1 − 0.8

= (0.8)3 = 0.512.

Alternatively,

P(F ≥ 3) = 1 − (P(F = 0) + P(F = 1) + P(F = 2))

= 1 − (q + pq + p

2

q)

= 1 − (0.2)(1 + 0.8 + (0.8)2

)

= 1 − 0.488 = 0.512.

(c) How many throws on average will fail before she hits bull’s eye?

Since p = 0.8 and q = 0.2, the expected number of failures before the first success

is

E[F] = p

q

=

0.8

0.2

= 4.

7 0
3 years ago
Read 2 more answers
To obtain an estimate of the proportion of "full time" university students who have a part time job in excess of 30 hours per we
musickatia [10]

Answer:

2,436 students

Step-by-step explanation:

At a 90% confidence level, the z-score is 1.645 and the confidence interval is given by:

x\pm z\frac{s}{\sqrt n}

Where s is the standard deviation, and  n is the sample size.

If they want the length of their confidence interval to be no greater than 0.2, it must be no further than 0.1 from the mean 'X':

0.1>1.645\frac{3}{\sqrt n}\\\sqrt n>1.645*30\\n>2,435.42

Rounding up to the next whole number, the sample size should be 2,436 students.

5 0
4 years ago
What is the slope of the line on the graph? Enter your answer in the box. A coordinate grid that includes the line y equals nega
RUDIKE [14]

we have

the equation of the line is y=-2x

the points are

A(3,-6)\\B(0,0) \\C(-3,6)

<u>Method 1</u>

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

In this problem we have a direct variation

The constant of proportionality k is equal to the slope of the line

k=-2

so

m=-2

therefore

<u>the answer is</u>

the slope of the line is equal to

m=-2

<u>Method 2</u>

we know that

the formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

A(3,-6)\\B(0,0)

substitute in the formula

m=\frac{0+6}{0-3}

m=\frac{6}{-3}

m=-2

therefore

<u>the answer is</u>

the slope of the line is equal to

m=-2


3 0
4 years ago
Read 2 more answers
∆ABC is similar to ∆DEF. The ratio of the perimeter of ∆ABC to the perimeter of ∆DEF is 1 : 10. The longest side of ∆DEF measure
Mkey [24]

we know that


1) scale factor is equal to \frac{1}{10}


2) The ratio of the perimeters of the triangles is equal to the ratio of the measures of the sides


3) the longest side of ∆ABC=[scale factor]*the longest side of ∆DEF

the longest side of ∆ABC=\frac{1}{10}*40

the longest side of ∆ABC=4 units


the answer part a) is

the longest side of ∆ABC is 4 units


Part b)

The ratio of the area of ∆ABC to the area of ∆DEF is equal to the scale factor squared

so

[scale factor]^{2} =(\frac{1}{10})^{2} \\ \\ =\frac{1}{100} \\ \\ =0.01


therefore


the answer part b) is

The ratio of the area of ∆ABC to the area of ∆DEF is \frac{1}{100}

6 0
3 years ago
Read 2 more answers
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