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taurus [48]
3 years ago
11

356÷3

} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0
Oh you can use photo math for This
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In a sale, a clothes shop reduces its prices by 30%.
ipn [44]

Answer:

$16.80

Step-by-step explanation:

30% of 24 and the answer is subtracted from $24

8 0
2 years ago
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Could someone please help me with this problem? I don't understand.
sasho [114]
Try dividing 150 by 2 1/2 and your answer would be 6.25 you may want to double check that math though
4 0
3 years ago
This rational expression is nonequivalent. 5x / 25x^4 ; x^3 / 5x^15<br> True or false?????
FromTheMoon [43]

It is nonequivalent. Figure it out this way. Think about what number has to be multiplied by both the numerator and the denominator of \frac{5x}{25x^4} to get to \frac{x^3}{5x^15}. It has to be the samee number for the one expression to be equivalent to the other. To get from 5x to x^3, we have to multiply by 1/5x^2. When we do that we get x^3. Good. Now we have to multiply the denominator by the same thing, 1/5x^2. 25x^4(\frac{1}{5}x^2)=5x^6. As you can see, they are not equivalent.

8 0
4 years ago
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WORTH 100 POINTS!!!!!
aleksklad [387]

Answer:

1. This graph is not a function, because for every y there are more than one x.

2. This graph is not linear because it is not a straight line.

3. It took them 6 hours to get to their destination.

4. The destination was 325 miles away.

5. They might have stopped at a restaurant to eat.

6 0
2 years ago
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A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t
Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

h=-16t^2+200t

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

350=-16t^2+200t

The last is a quadratic equation, which can be put in the form at^2+bt+c=0 and solved applying the formula:

t=\frac{-b+-\sqrt{b^2-4ac} }{2a}

So, let's put the equation on the form at^2+bt+c=0 adding 16t^2 and subtracting 200t to each side of the equation; the result is:

16t^2-200t+350=0

So, we note that a=16, b=-200, and c=350.

Then,

t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10

t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0
3 years ago
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