Answer:
Given: Segment AB || segment DE, C is the midpoint of segment DB.
Prove: ΔA CB ≅ ΔE CD
Proof: In ΔA CB and ΔE CD
C is the Mid point of B D.
BC=C D→ definition of midpoint
∠A CB= ∠ EC D→→vertical angles are congruent
∠BAC=∠DEC→→[AB║DE,so alternate angles are equal]
→→ΔA CB ≅ ΔE CD[A AS or A SA]
Option B: vertical angles are congruent
Answer:
-(-3) ± √(-3)^2 - 4(2)(-5) / 2(2) (the last choice).
Step-by-step explanation:
Im ignoring the 2^2 in the equation
The equation transforms to
2x^2 - 3x - 5 = 0 (standard form)
So x = -(-3) ± √(-3)^2 - 4(2)(-5) / 2(2)
Answer:
140
Step-by-step explanation:
183-37=146
We know the order of operations, right? PEMDAS
Parenthesis
Exponents
Multiplication
Division
Addition and
Subtraction.
So, by using the order of operation, it would come out to:
-24
But I don't see that as an answer choice... a typo maybe? :) Hope this helps anyways!
I assume you are asking what percent is 255 out 0f 300. And the answer to that is 85%
