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il63 [147K]
3 years ago
14

The ratio of girls to boys in a class is 3:2. There are 25 students in this class. How many are girls and how many are boys?

Mathematics
1 answer:
IrinaK [193]3 years ago
4 0
10 boys and 15 girls
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Evaluate the following expression.<br> 12÷4×32+(4−2)5
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answer is 111

Step-by-step explanation:

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Can you multiply a coefficient by a constant
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yes

because coefficient and constant can be multiplied or divided for example 5x * 7 equals 35 but if you are coefficient and constant you couldn't like an example 7 + 6x equals 7 + 6x

6 0
3 years ago
find the coordinates of the points D ( 4, -4 ) and E ( 5, -5 ) after the transformation ( x; y ) ( x + 3, y -5
postnew [5]

Answer:

second option

Step-by-step explanation:

Given the rule

(x, y ) → (x + 3, y - 5)

This means add 3 to the original x- coordinate and subtract 5 from the original y- coordinate, that is

D(4, - 4 ) → D'(4 + 3, - 4 - 5 ) → D'(7, - 9 )

E(5, - 5 ) → E'(5 + 3, - 5 - 5 ) → E'(8, - 10 )

7 0
3 years ago
Marie can find the volume of a cube by using the formula V = 53, where s represents the side length of the cube. If Marie's
dimulka [17.4K]

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The volume of her cube is 15.625cm^3

Step-by-step explanation:

The formula V = s³, where s represents the side length of the cube.

6 0
3 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
2 years ago
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