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Zina [86]
3 years ago
10

(I WILL GIVE DA BRAINLIEST) Mackenzie and Roger both leave the park at the same time walking in opposite directions. Mackenzie w

alks 5 miles per hour, and Roger walks 6 miles per hour. Which equation represents the distance d between them t hours after they have left the park?
Mathematics
1 answer:
Margaret [11]3 years ago
5 0
(5+6=miles per hour)
i hope this helps
so look...
m=miles
(5m+6=m)<------ answer
hope this helps

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A company plans to manufacture a rectangular bin with a square base, an open top, and a volume of 800 cm3. The cost of the mater
Nesterboy [21]

Answer:

The dimensions of the box is 20 cm by 20 cm by 2 cm.

The minimum cost of manufacturing the box is 120 cents.

Step-by-step explanation:

Given that, the volume of of rectangular is 800 cm³ with a square base, an open top.

Consider the side of the square base is x cm.

Then length = width = x cm.

and the height be h cm.

The volume of the box is = length×width×height

                                          =(x.x.h) cm³

                                          =x²h cm³

Therefore

x²h=800

\Rightarrow h=\frac{800}{x^2}

The area of the base is = x² cm²  [ since the base is square in shape]

The area of the sides = 2 (length×width) height

                                    =2(x+x)h cm²

                                    =2(2x)h cm²

                                    = 4xh   cm²

The cost of the material for the base is 0.1 cents per square and the cost of the material for the the sides is 0.5 cents.

Total cost of material is C(x)=[(x²h×0.1)+ (4xh×0.5)] cents

∴ C(x)=[(x²×0.1)+ (4xh×0.5)]

⇒C(x)=(0.1x²+2xh)

Putting h=\frac{800}{x^2}

C(x)= 0.1 x^2+2x.\frac{800}{x^2}

\Rightarrow C(x)= 0.1 x^2+\frac{1600}{x} .......(1)

Differentiating with respect to x

C'(x)=0.2x-\frac{1600}{x^2}

Again differentiating with respect to x

C''(x)=0.2+\frac{3200}{x^3}

To find the maximum or minimum cost, we set C'(x)=0

\therefore 0.2x-\frac{1600}{x^2}=0

\Rightarrow 0.2x=\frac{1600}{x^2}

\Rightarrow 0.2x^3=1600

\Rightarrow x^3=\frac{1600}{0.2}

\Rightarrow x^3=8000

\Rightarrow x=20

At x=20 ,the value of C(x) >0. Then at x=20 the value of cost will be maximum.

At x=20 ,the value of C(x) <0. Then at x=20 the value of cost will be minimum.

\therefore C''(x)|_{x=20}= 0.2+\frac{3200}{20^3}>0

The cost of manufacturing the box is minimum when x=20 cm.

Then the height h =\frac{800}{20^2}

                              =2 cm.

The dimensions of the box is 20 cm by 20 cm by 2 cm.

Now putting the value of x in (1)

\therefore C(20)= 0.1\times 20^2+\frac{1600}{20}

            =120 cent.

The minimum cost of manufacturing the box is 120 cents.

6 0
3 years ago
Which one of these things from the natural world exhibits perfect symmetry
Paul [167]

Answer:

The answer is D I hope this helps and is correct

Step-by-step explanation:

5 0
3 years ago
The following frequency table relates the weekly sales of bicycles at a given store over a 42-week period.
7nadin3 [17]

Answer:

14

Step-by-step explanation:


6 0
3 years ago
For what values of x is x2-36=5x true?<br> 0 -9 and -4<br> O4 and 9<br> O4 and -9<br> o 9 and 4
mars1129 [50]

Answer:

-4 and 9

Step-by-step explanation:

we have

x^{2} -36=5x

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} -36=5x

x^{2}-5x-36=0

so

a=1\\b=-5\\c=-36

substitute in the formula

x=\frac{-(-5)(+/-)\sqrt{-5^{2}-4(1)(-36)}} {2(1)}

x=\frac{5(+/-)\sqrt{169}} {2}

x=\frac{5(+/-)13} {2}

x=\frac{5(+)13} {2}=9

x=\frac{5(-)13} {2}=-4

therefore

The equation is true for -4 and 9

4 0
3 years ago
1. Are there more inches in a mile or second in a day?​
lawyer [7]

1day-24hours-60min-0.0167seconds

miles to inches = 63360

4 0
4 years ago
Read 2 more answers
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