Please help me!!! solve for f : 5/6 f =5 1. 5 2. 4.2 3. 7.3 4. 6

6-1 reteach solving systems by graphing

timofeeve [1]

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7 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

PLEASE HELP ME ON MY FIRST QUESTION!, SHOW WORK PLEASE!!

kvasek [131]

Answer:

Solution given:

radius [r]=2cm

height [h]=8cm

total surface area of cylinder=?

we have

total surface area of cylinder=2πr²+2πrh

2πr(r+h)
2π*2(2+8)
40π or 125.66cm²

total surface area of cylinder40π or 125.66cm².

3 0

2 years ago

Read 2 more answers

Find the values of the pronumerals in this diagram. Write down the reason in each case.

timofeeve [1]

Answer:

see explanation

Step-by-step explanation:

a and 85 form a straight angle and are supplementary, thus

a + 85 = 180 ( subtract 85 from both sides )

a = 95

b and 85 are vertical angles and are congruent, thus

b = 85

c and 85 are corresponding angles and congruent, thus

c = 85

c and d are vertical angles and congruent, thus

d = 85

In conclusion

a = 95, b = 85, c = 85, d = 85

5 0

2 years ago

What is the scale factor in the dilation ? 1/6 1/3 3 6

anzhelika [568]

Answer:

3

Step-by-step explanation:

1) Find two corresponding lengths between the image and the pre-image

Pre-image (bottom side) = 3 units

Image (bottom side) = 9 units

We can use any corresponding lengths for this step.

2) Divide the length of the side from the image by the length of the side from the pre-image

9 units ÷ 3 units

= 3

Therefore, the scale factor of the dilation is 3.

I hope this helps!

5 0

3 years ago

Read 2 more answers