Answer:
Step-by-step explanation:
(a) H0: μ_D=0
Ha: μ_D ≠ 0
b) Find attached the solution
(c) By technology,
p - value = 0.4437
Hence,
the p-value is 0.4437
The subtraction gives -7x^2( x + 1) - 3
<h3>What are algebraic expressions?</h3>
Algebraic expressions are expressions are expressions that are made up of factors, terms, variables and constants.
They also consist of arithmetic operations.
We have to subtract (6x^3 − x^2 + 8x + 5) from (−x^3 − 9x^2 + 2)
It is written as;
(−x^3 − 9x^2 + 2) - (6x^3 − x^2 + 8x + 5)
−x^3 − 9x^2 + 2 - 6x^3 + x^2 - 8x - 5
collect like terms
-x^3 - 6x^3 - 9x^2 + x^2 + 2 - 5
Add like terms
-7x^3 - 7x^2 - 3
To simply further
-7x^2( x + 1) - 3
Thus, the subtraction gives -7x^2( x + 1) - 3
Learn more about algebraic expressions here:
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For this case we have the following functions:
We must find . By definition we have to:
So:
We add similar terms:
Answer:
Option D
Well, lets look at it this way ... tell me if this does anything for you:
-- Take the number 31.01 .
-- Stick a zero on the end and make it 31.010 .
-- Zeros at the end of a number after the decimal point don't change
the value of the number. So you haven't changed the value of 31.01 .
-- But now it looks exactly like the other number !
-- They must be equal.
Does this float your boat at all ?
Answer:
θ = 36.94°
Step-by-step explanation:
Brewster's law for polarization states that; tan(θ_p) = n2/n1
Where ;
θ_p is the polarizing angle
n1 is the index of refraction of first material
n2 is the index of refraction of second material
Now, our first material here is air while second material is water.
Index of refraction of water = 1.33 while index of refraction of air is 1
Thus,
tan(θ_p) = n2/n1 = 1.33/1
tan(θ_p) = 1.33
(θ_p) = tan^(-1)1.33
(θ_p) = 53.06°
Now, polarizing angle is the angle of incidence for which all the reflected light is polarized and it's above the vertical. Thus to get the angle to the horizontal, it will be;
θ = 90° - (θ_p) = 90° - 53.06° = 36.94°