bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.
le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.
8/15 or somthing like that it you might be souposed to solve it diferent than i did
Answer:
b is correct answer
Step-by-step explanation:
hope it helped
Answer:
Step-by-step explanation:
given
the factor (x - 3) can be cancelled from the numerator/ denominator leaving