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meriva
2 years ago
15

What is the coefficient of the third term in this expression? 5b³ - 10 + 4c³?​

Mathematics
1 answer:
mihalych1998 [28]2 years ago
4 0

Answer:

4

Step-by-step explanation:

A coefficient is a number before the variable. The third term is 4c^3, and the coefficient is 4.

Hope this helps!

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The table represents an exponential function.
polet [3.4K]

Answer:

N

Step-by-step explanation:

7 0
3 years ago
The volume of a prism is the product of its height and area of its base, V = Bh. A rectangular prism has a volume of 16y4 + 16y3
Zepler [3.9K]

Answer:

We have a prism with a volume of 16y⁴ + 16y³ + 48y² cubic units.

Its volume is equal to the area of its base times its height.

Of course, for those to be the base area and height of this prism, they would have to multiply to 16y⁴ + 16y³ + 48y² cubic units.

Let's test each of these answers to see which gives us the correct volume.

--------------------------------------------------------------------------------------------------

a base area of 4y square units and height of 4y² + 4y + 12 units

We find the volume by multiplying the base area by the height...

4y(4y² + 4y + 12)

Distribute the 4y to each term inside the parentheses.

16y³ + 16y² + 48y

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 8y² square units and height of y² + 2y + 4 units

We find the volume by multiplying the base area by the height...

8y²(y² + 2y + 4)

Distribute the 8y² to each term inside the parentheses.

8y⁴ + 16y³ + 32y²

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 12y square units and height of 4y² + 4y + 36 units

We find the volume by multiplying the base area by the height...

12y(4y² + 4y + 36)

Distribute the 12y to each term inside the parentheses.

48y³ + 48y² + 432y

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 16y² square units and height of y² + y + 3 units

We find the volume by multiplying the base area by the height...

16y²(y² + y + 3)

Distribute the 16y² to each term inside the parentheses.

16y⁴ + 16y³ + 48y²

The volume fits, so these could be the base area and height of our prism.

--------------------------------------------------------------------------------------------------

D. a base area of 16y² square units and height of y² + y + 3 units

--------------------------------------------------------------------------------------------------

Step-by-step explanation:

7 0
3 years ago
I need help please! this is on EDGE2020 !
Margaret [11]

Answer:

D

Step-by-step explanation

A. there are 6 triangles so not this

B. Only 2 rectangles

C. 6 triangles once again

D. everything matches

5 0
3 years ago
Read 2 more answers
Of the following situations, which is best represented by the product<br> 5x(-3)?
anygoal [31]

Answer:

=-5x

Step-by-step explanation:

Remove   parentheses   (-a)=-a

= -5x.3

hoped i helped :) can i get brainiest

3 0
3 years ago
Given limit f(x) = 4 as x approaches 0. What is limit 1/4[f(x)]^4 as x approaches 0?
stepladder [879]

Answer:

\displaystyle 64

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Limit Rule [Variable Direct Substitution Exponential]:                                         \displaystyle \lim_{x \to c} x^n = c^n

Limit Property [Multiplied Constant]:                                                                     \displaystyle \lim_{x \to c} bf(x) = b \lim_{x \to c} f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle  \lim_{x \to 0} f(x) = 4

<u>Step 2: Solve</u>

  1. Rewrite [Limit Property - Multiplied Constant]:                                           \displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4} \lim_{x \to 0} [f(x)]^4
  2. Evaluate limit [Limit Rule - Variable Direct Substitution Exponential]:       \displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4}(4^4)
  3. Simplify:                                                                                                         \displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = 64

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

3 0
3 years ago
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