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tigry1 [53]
3 years ago
15

( −2 x^3) ^ 3 simplify

Mathematics
2 answers:
Leni [432]3 years ago
8 0
Your answer is -8x^9
densk [106]3 years ago
5 0

Answer:

-8x^9

Step-by-step explanation:

We can split up the exponent into multiple products: (-2x^3)^3=(-2)^3*(x^3)^3.

We know that (-2)^3=(-2)*(-2)*(-2)=-1*-1*-1*2*2*2=-1*8=-8.

We also know that (x^3)^3=x^{3*3}=x^9.

So, our answer is \boxed{-8x^9} and we're done!

You might be interested in
(3x - 9) + x + (x + 28) = 184.
julia-pushkina [17]

Answer:

33

Step-by-step explanation:

rearrange and combine like terms

(3x - 9) + x + (x + 28) = 184

3x - 9 + x + x + 28 = 184

3x + x + x + 28 - 9 = 184

3x + x + x = 184 + 9 - 28

5x = 165

x = 33

3 0
3 years ago
Read 2 more answers
Which represents a total cost of 4 dance tickets at a price of c for each, less a one-time $3 discount?
nalin [4]

Answer:

4(c)- 3

Step-by-step explanation:

i chose this answer because if there are 4 tickets and each one is c(?) which is an unknown amount in this equation. First youd have to multiply 4 by c to find the total amount and since they are giving a discount of $3 you subtract $3 from the total.

8 0
1 year ago
Find all solutions in the interval [0, 2π).<br><br> 4 sin2x - 4 sin x + 1 = 0
Eddi Din [679]

Answer:

x = π/6, 5π/6

Step-by-step explanation:

4 sin² x − 4 sin x + 1 = 0

(2 sin x − 1)² = 0

sin x = ½

x = π/6, 5π/6

5 0
3 years ago
Find the value of x. <br> A) 10 <br> B) 4<br> C) 6<br> D) 7
andrew11 [14]

Answer:

10

Step-by-step explanation:

4 0
3 years ago
A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
denpristay [2]

Answer:

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0
4 years ago
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