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2 years ago

The graph of function f is shown above. if g(x)=x^2/f(x) what is the value of g'(1)?

Mathematics

1 answer:

Alla [95]2 years ago

7 0

Answer:

Step-by-step explanation:

Find the equation of the segment going from (0,-5) to (3,7)

y intercept = -5

Slope = (-5 - 7) / (0 - 3) = -12/-3 = 4

equation: y = 4x - 5

g(x) = x^2 / f(x)

f(x)= (4x - 5)

g(x) = x^2 / (4x - 5)

g'(x) = x^2 * (4x - 5)^-1

g'(x) = 2x*(4x - 5)^-1 + (-1) *4* x^2 (4x - 5)^-2

I will leave that monster the way it is and just find g'(1)

g'(1) = 2(1) * (4(1) - 5)^-1 + (-1) (1)^2 *4* (4(1) - 5)^-2

g'(1) = 2(1) * (-1)^-1 + (-1) (1)^2 *4 * (-1)^2

g'(1) = -2 + (-1) (1)^2 (4)

g'(1) = - 2 + (-1) (1)^2 (4)

g'(1) = - 2 - 4

g'(1) = - 6

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2 years ago

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Answer:

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Step-by-step explanation:

Given the bacteria on the counter is initially measured at 5 and doubles every 3 days we can generate the following geometric equation:

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To find how many days it will take for the bacteria population to equal the same lets set both equations equal to eachother:

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1 year ago

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Andreas93 [3]

Answer:

Step-by-step explanation:

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1 year ago

A pebble falls of a cliff at a height of 256 ft. If the equation for the height as a function is h(t)=-16^2 + initial height whe

AlladinOne [14]

Answer:

After 4secs

Step-by-step explanation:

Given the function of the height expressed as;

h(t)=-16^2 + initial height

If initial height = 256, then;

h(t) = -16t^2 + 256t

The pebble will hot the ground at when h(t) = 0

Substitute

0 = -16t^2 + 256t

16t^2 = 256

t^2 = 256/16

t^2 = 16

t = 4

Hence the pebble will hit the ground after 4secs

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2 years ago

What is 2/3 + -1/4 = plz help lol I’m lost <br> :)

alexgriva [62]

It is 0.416. The answer

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2 years ago

Read 2 more answers

The graph of function f is shown above. if g(x)=x^2/f(x) what is the value of g'(1)?​

The graph of function f is shown above. if g(x)=x^2/f(x) what is the value of g'(1)?