When we have consecutive values, f(10), f(11), f(12), f(13), f(14), we can make a difference table to determine the degree of f as a polynomial. A quadratic will have a constant second difference:
x 10 11 12 13 14
f(x) 50 71 94 119 146
1st diff 21 23 25 27
2nd diff 2 2 2
We got a constant second difference, so f is a polynomial of degree two.
Answer: This function is quadratic
Answer:
its 9
Step-by-step explanation:
I have gotten it correct on ED
Answer:
14.25
Step-by-step explanation:
14 25/100= 14*100+25/100=
1400+25/ 100
= 1425/100
= 14.25
You distribute -4 to each in the parentheses then you get -24 - 4b = 4 then you add 24 on both sides and get -4b = 28 then you divide each side by -4 and it equals -7
You plug in 2x + 4 into the y for the other equation (3x +y ) and solve for it