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stiv31 [10]
3 years ago
14

What is the solution of the inequality shown below? w + 4 > 0

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:

w>-4

Step-by-step explanation:

w+4>0

w+4-4>0-4

w>-4

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Which of these expressions is equivalent to 3 (x -2)
DaniilM [7]

Answer:

3 (x -2) = 3x - 6

4 0
3 years ago
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Suppose that ​$17,183 is invested at an interest rate of 5.4​% per​ year, compounded continuously. ​a) Find the exponential func
Pavlova-9 [17]

Answer:

Total = Principal * e ^ (rate * years)

Total = 17,183 * 2.718281828459 ^ (.054 * years)

After 1 year = 18,136.39

After 2 years = 19,142.68

After 5 years = 22,509.12

After 10 years = 29,486.15

We'll use this formula to find the doubling time:

Years = ln (total / principal) / rate

we'll use 200 for total and 100 for principal

Years = ln (200 / 100) / rate

Years = ln (2) / .054

Years = 0.69314718056 / .054

Years = 12.8360588993  Years Doubling Time

Step-by-step explanation:

8 0
3 years ago
A solid has 14 faces and 12 vertices. How many edges does the solid have? A. 18 edges B. 20 edges C. 22 edges D. 24 edges
sladkih [1.3K]

Answer: D 24

Step-by-step explanation:

7 0
3 years ago
Find the perimeter RST. Round answer to the nearest tenth<br> Show all the work
kow [346]

Answer:

35.1 units

Step-by-step explanation:

Imagine a right-angled triangle with RS as hypotenuse. The base would be 3 units and the height would be 6 units. By Pythagorus:

RS²=3²+6²

RS=\sqrt{45}≈6.7 units

Imagine a right-angled triangle with RT as hypotenuse. The base would be 9 units and the height would be 12 units. By Pythagorus:

RT²=9²+12²

RT=\sqrt{225} = 15 units

Imagine a right-angled triangle with TS as hypotenuse. The base would be 12 units and the height would be 6 units. By Pythagorus:

TS²=12²+6²

TS=\sqrt{180}≈13.4 units

Perimeter=RS+RT+TS

=6.7+15+13.4

=35.1 units

6 0
3 years ago
The symmetry of a hyperbola with a center at (h, k) only occurs at y = k. True or False
Vikki [24]
A hyperbola with a center at (0, 0) can be defined  as x²/a² − y²/b² = ±1.<span> 
</span>The statement "<span>The symmetry of a hyperbola with a center at (h, k) only occurs at y = k" </span>is false, because a hyperbola have many different orientations.
It doesn't have to be symmetric about the lines y = k or x = h.
6 0
3 years ago
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