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Lostsunrise [7]
3 years ago
10

A stockbroker knows from experience that the probability that a client owns stocks is 0.60. P(A) The probability that a client o

wns bonds is 0.50. P(B) The probability that the client owns bonds if he/she already owns stock is 0.55 What is the probability of a client owning stocks OR bonds
Mathematics
1 answer:
Irina18 [472]3 years ago
6 0

Answer:

the probability of a client owning stocks OR bonds is 0.825

Step-by-step explanation:

The computation of the probability of a client owning stocks OR bonds is given below:

= P(stocks) + P(bonds) - P(stocks and bonds)

= 0.60 + 0.50 - (0.55 × 0.50)

= 0.60 + 0.50 - 0.275

= 0.825

Hence, the probability of a client owning stocks OR bonds is 0.825

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(If this question is easy, I am just horrible with percentages, lol :p)
Sati [7]
55% of 20 is 11. the answer is 20
5 0
2 years ago
Multiply and simplify the product. –12i × 3i Select the product. 36 -36 36i -36i
bazaltina [42]

Answer:

36

Step-by-step explanation:

–12i × 3i

Multiply the numbers

-12*3 = -36

Multiply the imaginary number

i*i= i^2

We know i^2 = -1

-36 * -1 = 36

4 0
3 years ago
Read 2 more answers
A cell phone costs 120 dollars. The price reduced 30% for a sale. How much is the savings
Licemer1 [7]

Answer:

You save 36 dollars.

Step-by-step explanation:

30% of 120 is 36.

You spend $84

5 0
2 years ago
Help I’m not sure with this one!! Urgent help
Nastasia [14]

This system has exactly one solution, because the two equation are linearly independent (i.e. one is not a multiple of the other).

We can explicitly find the solutions: from the first equation we deduce

x = \dfrac{c-by}{a}

Plug this value for x in the second equation:

\dfrac{a}{3}\cdot \dfrac{c-by}{a}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{c-by}{3}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{2(c-by)+3by}{6}=\dfrac{c}{6}

Multiply both sides by 6 to get

2(c-by)+3by=c \iff 2c-2by+3by=c \iff by=-c \iff y=-\dfrac{c}{b}

Plug this value for y in the expression for x:

x = \dfrac{c-by}{a} = \dfrac{c-b\cdot\frac{-c}{b}}{a}=\dfrac{2c}{a}

Since both a,b are not zero, both solutions are well defined.

8 0
3 years ago
Researchers recorded that a certain bacteria population declined from 120,000 to 200 in 36 hours. At this rate of decay, how man
quester [9]

Answer: There will 486 bacteria in 31 hours.

Step-by-step explanation:

The population decay in bacteria is exponential.

Exponential function : y=Ab^x, where A = initial population, b multiplication decay factor, t= time:

As per given:

Initial population: A=120,000

After 36 hours, population = 120000(b^{36})=200

Divide both sides by 120,000 we get

b^{36}= 0.00167

Taking natural log on both sides , we get

36\ln b=\ln 0.00167\\\\\Rightarrow\ b=e^{\left(\frac{\ln0.00167}{36}\right)}=0.83724629\approx0.8372

At x= 31,

y=120000(0.8372)^{31}=120000\times0.00405234\approx486

Hence, there will 486 bacteria in 31 hours.

4 0
3 years ago
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