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3 years ago

Well ,How to put a question on brainly? please help ASAP

Mathematics

2 answers:

REY [17]3 years ago

7 0

Answer:

congrats, you just put a question

anyways have a nice day and thanks for the pointssss

tekilochka [14]3 years ago

4 0

Answer:

How did you post this question if you don't no how to post a question on brainly lol.

Step-by-step explanation:

You press the button that say's ask question and you ask what ever question you want to, but don't post wired stuff please.

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At the farmers market, Nathaniel buys two dozen oranges at $3.50 per dozen, four kilograms of apples at $3.25 per kilogram, two

kirill [66]

Nathaniel's total cost is $(3.50 x2 + 3.25 x4 +1.90 x2 +1.20) = $24 he got 5% off so he paid $24- (24* 5/100) =$22.80

3 0

3 years ago

Can you help me out? In a test

NikAS [45]

Answer:

Step-by-step explanation:

8 0

3 years ago

Question 17/23

disa [49]

Answer:

60%

Step-by-step explanation:

Formula:

Percentage decrease = (amount of decrease)/(original price)

✪ Solve ✪

3.85 - 1.54/3.85 x 100

2.31/3.85 x 100 = 60%

Hence, Percent decrease is 60%

<em>~Lenvy</em>

6 0

2 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

How would you write 20% as a fraction

givi [52]

For 20% out of 100% it would be 1/5 as you need 5 20s for 100

6 0

3 years ago

Read 2 more answers

Well ,How to put a question on brainly? please help ASAP​

Well ,How to put a question on brainly? please help ASAP