I’m pretty sure the answer is Barium. I hope it helps.
The answer would be heptan-3-one and heptan-4-one.
The acid-catalyzed hydration of a balanced alkyne gives a
ketone.
R-C≡C-R + H₂O → R-CH₂-CO-R
If the alkyne is uneven, you get a combination of two
ketones, since the O can increase to either of the alkyne C atoms.
R-C≡C-R' + H₂O → R-CH₂-CO-R' + R-CO-CH₂-R'
So, for CH₃CH₂CH₂-C≡C-CH₂CH₃, the products are
CH₃CH₂CH₂-CH₂-CO-CH₂CH₃ and CH₃CH₂CH₂-CO-CH₂-CH₂CH₃
Their terms are heptan-3-one and heptan-4-one,
Answer:
The nucleus contains crotons and neutrons with electrons on the outer shell
Hope this helps!
We are given the molar mass of Molybdenum as 95.94 g/mol. Also, the chemical symbol for Molybdenum is Mo. This question is asking for the amount of molecules of molybdenum in a 150.0 g sample. However, since molybdenum is a metal and it is in the form of solid molybdenum, Mo (s), it is not actual a molecule. A molecule has one or more atom bonded together. We will instead be finding the amount of atoms of Molybdenum present in the sample. To do this we use Avogadro's number, which is the amount of atoms/molecules of a substance in 1 mole of that substance.
150.0 g Mo/ 95.94 g/mol = 1.563 moles of Mo
1.563 moles Mo x 6.022 x 10²³ atoms/mole = 9.415 x 10²³ atoms Mo
Therefore, there are 9.415 x 10²³ atoms of Molybdenum in 150.0 g.
