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3 years ago

N2 + 3H2 => 2 NH3

Chemistry

1 answer:

anyanavicka [17]3 years ago

7 0

Answer:

In the reaction above, the coefficient of H2 is 3. The subscript of H2 is 2.

Explanation:

N2 + 3H2 => 2 NH3

In the reaction above, the coefficient of H2 is 3. The subscript of H2 is 2.

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Jeffrey is on his skateboard and starts skating down a ramp. Ten seconds later he is travelling at

AfilCa [17]

Answer: 2m/s^2

Explanation:

Velocity of skateboard = 20.0 m/s.

Time taken = Ten seconds (10 s)

Acceleration = ?

Recall that acceleration is the change in velocity of a body per unit time.

i.e Acceleration = (velocity / Time)

Acceleration = 20.0m/s ➗ 10 s

Acceleration = 2m/s^2

Thus, Jeffrey acceleration was 2m/s^2

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3 years ago

How many hours does it take to form 15.0 L of O₂ measured at 750 torr and 30°C from water by passing 3.55 A of current through a

rosijanka [135]

Answer:

The correct answer is 17.845 hours.

Explanation:

To solve the question, that is, to determine the hours required there is a need to combine the Faraday's law of electrolysis with the Ideal gas law.

Based on Faraday's law, m = Mit/nF

Here m is the mass in grams, M is the molecular mass, i is the current in amperes, t is time, n is the number of moles of electron per mole of oxygen formed and F is the Faraday's constant (the value of F is 96487 coulombs/mole).

From the above mentioned equation,

t = mnF/Mi ------(i)

Now based on ideal gas law's, PV = nRT or PV = m/M RT, here n = mass/molecular mass.

So, from the above gas law's equation, m = PVM/RT

Now putting the values of m in the equation (i) we get,

t = PVMnF/MiRT = PVnF/iRT

Based on the given information, the value of P is 750 torr or 750/760 atm = 0.98 atm, the value of v is 15.0 L, T is 30 degree C or 273 + 30 K = 303 K, i is 3.55 Amperes, and the value of R is 0.0821 atm L/mol K.

1 mole of oxygen gives 2 moles of electrons, therefore, 2 moles of oxygen will give 4 moles of electrons.

Now putting the values we get,

t = PVnF/iRT

= 0.98 atm × 15.0 L × 4 moles of electron × 96487 coulombs per mole / 3.55 coulomb per sec × 0.0821 atm L per mole-K × 303 K

= 64243.81 secs or 64243.81/3600 hr

= 17.845 hours

7 0

3 years ago

Determine the mass of 1 mol of gold (Au), of aluminum chloride (AlCl3), and of glucose (C6H12O6)

sleet_krkn [62]

Answer: Mass of 1 mol of gold (Au) is 197g , of aluminum chloride $(AlCl_3)$ is 133.5 g and of glucose $(C_6H_{12}O_6)$ is 180 g

Explanation: Mass of 1 mole of a substance is called its molar mass.

a) 1 mole of $Au$ contains $6.023\times 10^{23}atoms$ and weigh 197g.

b) 1 mole of $AlCl_3$ will weigh= $1\times {\text {mass of 1 mole of Aluminium}}+3\times {\text {mass of 1 mole of chlorine atom}}$

Thus mass of 1 mole of $AlCl_3$ will be $=1moles\times {27g/mol}+3moles\times {35.5g/mol}=133.5g$

c) 1 mole of $C_6H_{12}O_6$ will weigh= $6\times {\text {mass of 1 mole of carbon}}+12\times {\text {mass of 1 mole of hydrogen atom}}+6\times {\text {mass of 1 mole of oxygen}}$

1 mole of $C_6H_{12}O_6$ will weigh= $6\times 12g/mol+12\times 1g/mol+6\times 16g/mol=180g$

5 0

3 years ago

How many bonds will an atom of bromine usually form in order to reach an octet of electrons?

irga5000 [103]

Answer:

So fluorine and bromine are halogens and when you work out the Lewis dot structure you'll see that they each have one unpaired electron, therefore these unpaired electrons join together to form one bond.

5 0

2 years ago

Read 2 more answers

At night, an equilibrium reaction between two different nitrogen compounds generates N2O5N2O5 in the atmosphere, as represented

kakasveta [241]

The breakdown of NO3 in the day leads to more consumption of N2O5 in the day hence its concentration is greater at night than in the day.

<h3>What is equilibrium constant?</h3>

The equilibrium constant is a number that shows how much reactants are converted to products in a reaction. It is often shown as capital letter K in English.

Given the situation described in the question, we know that the concentration of N205 will be higher at night, because the decomposition of NO3(g) in the daytime will result in an increase in the rate of consumption of N2O5(g) to reform NO3(g).

Learn more about equilibrium constant: brainly.com/question/17960050

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2 years ago