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lesantik [10]
3 years ago
10

If one zero of the polynomial 2x² + 3x + λ is 1/2, find the value of λ and other zero.​

Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0

The value of λ is - 2 and other zero is also - 2.

<h3>Justification:</h3>

Let <u>p(x) = 2x² + 3x + λ</u>

<u>Its one zero is 1/2</u>, so p(1/2) = 0

p(1/2) = 2 × (1/2)² + 3 × 1/2 × λ

⇒ 1/2 + 3/2 + λ = 0 ⇒ 4/2 + λ = 0

⇒ 2 + λ = 0 ⇒ λ = - 2

<u>Let the other zero be α</u>,

Then α + 1/2 = - 3/2 ⇒α = - 3/2 - 1/2 = - 2

Gekata [30.6K]3 years ago
7 0

Answer:

<u>Given</u>:– 2x² + 3x + λ

On comparing with ax² + bx + c = 0, we get

  • a = 2 b = 3 c = λ

So, plug the value of one zero

  • 2 × (1/2)² + 3 × 1/2 + λ = 0
  • 1/2 + 3/2 + λ = 0
  • 2 + λ = 0
  • λ = - 2

<u>Hence, the value of λ for given quadratic equation is -2</u>.

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