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Yuki888 [10]
3 years ago
13

ACCORDING to the rate of electricity charge, the minimum charge up to 20 unit is Rs 80 and the cost per unit from 21 units to 25

0 units is Rs 7.30. How many units were consumed by Rs 1248?
​
Mathematics
1 answer:
azamat3 years ago
6 0

Answer:

180

Step-by-step explanation:

let x = total units of electricity after 250 units

the total units of electricity consumed can be determined using the formula below

80 + 7.3x = 1248

7.3x = 1248 - 80

7.3x = 1168

divide both sides of the equation by 7.3

x = 1168 / 7.3

x = 160

total electricity consumed = 160 + 20 = 180

160

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Convert 1/4 to a decimal ​
ddd [48]

Answer:

0.25

Step-by-step explanation:

You divide the denominator (bottom) into the numerator (top).

1/4 = 1 / 4.00 = 0.25

8 0
3 years ago
What is the c.o.p. that describes the relationship between h and t.
Citrus2011 [14]
B is the answer to that question !!!
7 0
3 years ago
(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)
Elena L [17]

Answer:

\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

Step-by-step explanation:

\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1}  }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}

= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3}  - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a)} {2a+1}

= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

6 0
3 years ago
Customers who purchase an aluminum-structured Audi A8 can order an engine in any of three sizes: 2.0L, 2.4L, and 2.8L. Of all Au
sergiy2304 [10]

Answer:

The probability that an Audi A8 car with 2.4L engine is selected given that the car failed emissions test taken within four years of purchase is 0.3589.

Step-by-step explanation:

Let's denote event as follows:

<em>A</em> = an Audi A8 car has a 2.0L engine.

<em>B</em> = an Audi A8 car has a 2.4L engine.

<em>C</em> = an Audi A8 car has a 2.8L engine.

<em>X</em> = an Audi A8 car failed emissions test taken within four years of purchase.

The information provided is:

P(A)=0.45\\P(B)=0.35\\P(C)=0.20\\P(X|A)=0.10\\P(X|B)=0.12\\P(X|C)=0.15

The probability that an Audi A8 car with 2.4L engine is selected given that the car failed emissions test taken within four years of purchase is:

P(B|X)=\frac{P(X|B)P(B)}{P(X)}

Compute the probability of an Audi A*8 car failed emissions test taken within four years of purchase as follows:

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Compute the value of P (B|X) as follows:

P(B|X)=\frac{P(X|B)P(B)}{P(X)}=\frac{0.35\times0.12}{0.117} =0.3589

Thus, the probability that an Audi A8 car with 2.4L engine is selected given that the car failed emissions test taken within four years of purchase is 0.3589.

4 0
4 years ago
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valentina_108 [34]
I believe the correct answer from the choices listed above is the third option. All of the following proportions are equivalent except <span>a/d=c/b. 

</span><span>a/b=c/d

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a/d=c/b not equal to </span>a/b = c/d<span>

a/c=b/d => </span>a/b = c/d
7 0
3 years ago
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