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Basile [38]
3 years ago
9

(b) Without using a calculator, the square root of 18 will be between what two values (remember to look for perfect squares/perf

ect square roots)? Show your reasoning. You do not need to find the decimal equivalent of the root.
Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

Answer:

√18 = 3√2

Step-by-step explanation:

the square root of 18 = √18

18;

1 × 18 = 18

2 × 9 = 18

3 × 6 = 18

6 × 3 = 18

9 × 2 = 18

18 × 1 = 18

9 has a perfect square

So,

√18 = √(2*9)

= √2 * √9

= 3√2

√18 = 3√2

Perfect square

1 × 1 = 1

2 × 2 = 4

3 × 3 = 9

4 × 4 = 16

5 × 5 = 25

Therefore,

√18 is between 4 and 5

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can someone please do this for me and tell me how so I can do the other one pleaseeee I don't know what to do
KonstantinChe [14]

Answer:

P(green) =1/4

P(orange)=1/2

Step-by-step explanation:

I'm assuming this is probability but it\s been a while, so i'm not sure

number one is a square being divided into half and then one half is being divided into quarters. (as shown by the dotted lines and right angle)

so the probablity of landing in green is 1/4, because it is one fourth of the square.

the probability of the orange is 1/2 because it is 1/2 of the square

The same logic would apply to the "circle" i can see in the next problem. 120 degrees is 1/3 of 360, 90 is 1/4, and so on.

Hope that helps.

6 0
3 years ago
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Vladimir79 [104]

0,_4/3 yani sonıç E cevap bu fakat

7 0
3 years ago
Which is zero of the polynomial expression 7x+21
swat32

Answer:

The zero is x = -3

  1. Use the Rational Zero Theorem to list all possible rational zeros of the function.
  2. Use synthetic division to evaluate a given possible zero by synthetically dividing the candidate into the polynomial.
  3. Repeat step two using the quotient found with synthetic division.

Please Mark Brainliest If This Helped!

4 0
3 years ago
Read 2 more answers
Find the 7th term of the geometric sequence with the given terms.
Anarel [89]
The common ratio is the fifth term divided by the fourth term: -40/-8 = 5.
The seventh term is :
a_{7}=a_{5}\times5\times5=-40\times5\times5=-1000
8 0
3 years ago
Prove that:
photoshop1234 [79]
(a) 5^31-5^29 = 5^29(5^2-1)

 = 5^29(24)
 = 5^29(6)(4)
 =5^26(6)*[(5)(5)(4)]
 =5^26(6)*100
  (b) 25^9+5^17 = 5^18+5^17 
=5^17(5+1)
 =5^17(6)
 =5^16[(5)(6)]
 =5^16*30 
 (c) 27^10–9^14 = 3^30-3^28
 =3^28(3^2 -1)
 =3^28(8)
 =3^27[(3)(8)]
 =3^27*24

6 0
3 years ago
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