Ask question

Ask question

All categories

3 years ago

8

When rolling 3 standard number cubes, the probability of getting all three numbers to match is 6216. What is the probability tha

t the three numbers do not all match?

1 answer:

erik [133]3 years ago

6 0

Answer:

210/216

Step-by-step explanation:

because you would just do 216-6 and that equals 210

You might be interested in

A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc

Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

$-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)$

$\implies y_{\rm max}=57\,\mathrm m$

b. The ball's height in the air $y$ at time $t$ is given according to

$y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2$

Solve for $t$ when $y=0$ :

$17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s$

3 0

3 years ago

The total cost for potatoes, y, at a grocery store can be modeled by the equation y = 0.59x, where x is the number of pound of p

slavikrds [6]

Answer:

all nonnegative rational numbers

Step-by-step explanation:

6 0

3 years ago

Find the equation for a line passing through the point (2,-4) and (4,-6)

PIT_PIT [208]

Answer:

y=-1x-2

Step-by-step explanation:

y=mx+b is the easiest way to put the two points into a equation

8 0

3 years ago

Which would the phrase "the difference between a number and 2" look like as a variable expression

kompoz [17]

X-2 is the answer. hope this helps!

5 0

4 years ago

in 1940, the u.s. army reported a total of 17,563 commissioned officers. of these, 939 were females. find the percent of female

Kisachek [45]

Answer: The percent of female commissioned officers in the army in 1940= 5.3%

Step-by-step explanation:

We are given that ,

The number of commissioned officers reported by U.S. Army in 1940 = 17,563

The number of female commissioned officers = 939

Then , the number of female commissioned officers in the army in 1940 would be :-

$\dfrac{\text{\text{Number of Female officers}}}{\text{Total commissioned officers }}\times100$

$=\dfrac{939}{17563}\times100=5.3464670\approx5.3\%$

Hence, the percent of female commissioned officers in the army in 1940= 5.3%

3 0

3 years ago